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is r positive?

Expert replies
by uptowngirl92 » Sun Jul 19, 2009 6:53 pm
If r>s+t,is r positive?
1. s>t
2. r/s+t >1

[spoiler=]The OA is B[/spoiler]

Guys,Please help me find out where I went wrong.My solution:
Stmt. 1,
s>t.Taking values,
s=4,t=3 implies r is greater than 7.r is +ive.
s=4,t=-3 implies r is greater than 1.r is +ive
s=-3,t=-4 implies r is greater than -7.Can't say about r.
Hence,Stmt 1 is insufficient.

Stmt 2.
r/s+t>1
r>s+t....No new info.This is already mentioned in the ques.Hence insuff.so my answer came out (e)
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Source: — Data Sufficiency |

by mehravikas » Sun Jul 19, 2009 10:02 pm
Statement 1
S > t
S = 2, t = 1 – r would be +ve
S = -3, t = -4, r can be –ve

So insufficient

Statement 2
R / s + t > 1

R = 4, s = 1, t = 1 - result > 1
R = -1, s = -2, t = -1 – result < 1

Therefore, r has to be +ve to be greater than s + t, if R is negative, then statement 2 is false

Hence statement B is sufficient.

Also you cannot cross multiply if you are not sure whether the number being cross multiplied is +ve or –ve

Consider an example, -3 / -2 > 1, now according to you if I cross multiply, then -3 > -2, which is wrong. Because the number is negative the inequality sign should change

i.e. -3 < -2
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The 2nd option is

r/s+t >1


does that mean r/(s+t) > 1 or (r/s)+t>1....


Can you correct accordingly..
Anyone from Hyderabad or Telugu speaking community.

Searching for a serious study partner from Hyderabad or the one who work for same Company.
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by tohellandback » Sun Jul 19, 2009 10:42 pm
mehravikas wrote:Statement 1
S > t
S = 2, t = 1 – r would be +ve
S = -3, t = -4, r can be –ve

So insufficient

Statement 2
R / s + t > 1

R = 4, s = 1, t = 1 - result > 1
R = -1, s = -2, t = -1 – result < 1

Therefore, r has to be +ve to be greater than s + t, if R is negative, then statement 2 is false

Hence statement B is sufficient.

Also you cannot cross multiply if you are not sure whether the number being cross multiplied is +ve or –ve

Consider an example, -3 / -2 > 1, now according to you if I cross multiply, then -3 > -2, which is wrong. Because the number is negative the inequality sign should change

i.e. -3 < -2
well I don't think that statement B is sufficient
take t=1
s=-50
r=-1
here r>s+t
r/s +t >1
and r is negative

IMO C
The powers of two are bloody impolite!!
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by tohellandback » Sun Jul 19, 2009 11:01 pm
oh wait..I think I got it..so
its r/(s+t) and not r/s + t

statement 1) not SUFF

2)r/(s+t)>1
now uptowngirl you CANNOT write it as r>s+t, because if (s+t)<0, it will become r<s+t

so possibilities are
r>s+t, when (s+t)>0, so r>0
r<(s+t) when (s+t)<0- but this is not possible because it is given in the question that r>s+t
so SUFF

answer B
The powers of two are bloody impolite!!
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