5^n > 4,000,000

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5^n > 4,000,000

by sanju09 » Tue Nov 15, 2011 3:41 am
If n is an integer and 5^n > 4,000,000, what is the least possible value of n?
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
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by neelgandham » Tue Nov 15, 2011 3:47 am
5^n > 4,000,000
5^n > 4*(10^6)
5^n > 4*(5^6)*(2^6)
5^n > 256 * (5^6)
5^3<256<5^4

Min value of n = 10 IMO D
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by Anurag@Gurome » Tue Nov 15, 2011 3:47 am
sanju09 wrote:If n is an integer and 5^n > 4,000,000, what is the least possible value of n?
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
5^n > 4,000,000
5^n > 2² * 10^6
5^n > 2² * 2^6 * 5^6
5^n > 2^8 * 5^6
5^(n - 6) > 256
Now 5^4 = 625 > 256
So, n - 6 = 4
n = 10

The correct answer is D.
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by vipdst1 » Tue Nov 15, 2011 9:59 pm
Anurag@Gurome wrote:
sanju09 wrote:If n is an integer and 5^n > 4,000,000, what is the least possible value of n?
(A) 7
(B) 8
(C) 9
(D) 10
(E) 11
5^n > 4,000,000
5^n > 2² * 10^6
5^n > 2² * 2^6 * 5^6
5^n > 2^8 * 5^6
5^(n - 6) > 256
Now 5^4 = 625 > 256
So, n - 6 = 4
n = 10

The correct answer is D.
Hi, I got lost at:
This line: 5^n > 2^8 * 5^6

Could you explain its following:
5^(n - 6) > 256
Now 5^4 = 625 > 256

Thanks

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by neelgandham » Tue Nov 15, 2011 10:41 pm
Though directed to Anurag, I will try to explain it my way :)

5^n > 4,000,000
5^n > 2² * 10^6
5^n > 2² * 2^6 * 5^6
5^n > 2^8 * 5^6
5^(n - 6) > 256
125 < 256 < 625.
5^3 < 256 < 5^4
5^3 < 256 < 5^(n - 6)

Since we need the least integer value of n in 5^(n-6), the value of 5^(n-6) should be 5^4 which is the immediate next power of 5.
Now 5^4 = 5^(n-6)
So, n - 6 = 4
n = 10

Hope that helps !
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