Slope DS

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Slope DS

by aj5105 » Tue Jan 13, 2009 9:44 am
Line L passes through point (r,-s) and (t, u), is the slope of the line negative?
(1) r>t
(2) u>-s


want a easy way for this,please.
Source: — Data Sufficiency |

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by yalanand » Tue Jan 13, 2009 11:53 am
I will go for C....both options are required because


Slope of line = (r-t) / (-s-u)
= (r-t)/-(s+u)

So slope of the line will be negative if

r-t > 0 and s+u > 0 (u>-s)

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by aj5105 » Tue Jan 13, 2009 12:08 pm
This is what I was looking for !
yalanand wrote:I will go for C....both options are required because


Slope of line = (r-t) / (-s-u)
= (r-t)/-(s+u)

So slope of the line will be negative if

r-t > 0 and s+u > 0 (u>-s)

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by pbanavara » Tue Jan 13, 2009 12:11 pm
aj5105 wrote:This is what I was looking for !
yalanand wrote:I will go for C....both options are required because


Slope of line = (r-t) / (-s-u)
= (r-t)/-(s+u)

So slope of the line will be negative if

r-t > 0 and s+u > 0 (u>-s)
This is a clear and concise solution .. I was fretting with all unwanted facts and got confused. Thanks

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by yalanand » Tue Jan 13, 2009 12:18 pm
Welcome :)...and wish me BOF...I need all your wishes

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by welcome » Tue Jan 13, 2009 3:46 pm
Do we really need to go for C. I think A is enough.

Please clarify. If given r,t,u, -s are holding the sign, then by basic number prop. u+s will be +ve anyways.
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by logitech » Tue Jan 13, 2009 4:26 pm
yalanand wrote:I will go for C....both options are required because


Slope of line = (r-t) / (-s-u)
= (r-t)/-(s+u)

So slope of the line will be negative if

r-t > 0 and s+u > 0 (u>-s)
Slope = y1-y2/x1-x2

So even tough it does not change the answer, slope is = (u+s)/(t-r)
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by malhotneha » Wed Jan 14, 2009 11:20 am
welcome wrote:Do we really need to go for C. I think A is enough.

Please clarify. If given r,t,u, -s are holding the sign, then by basic number prop. u+s will be +ve anyways.
I agree. Even I think A is enough.

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by yalanand » Wed Jan 14, 2009 11:56 am
I still think its C....because r,t,u,s are all variables which can be +ve or -ve...

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by 4meonly » Thu Jan 15, 2009 12:39 am
I am also with C

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by duccio » Thu Jan 15, 2009 6:21 am
I'd go with A

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by duccio » Thu Jan 15, 2009 6:35 am
you are right, we actually do not know if r u t s are positive or negative
so A is INSUFF ===> C

yalanand wrote:I still think its C....because r,t,u,s are all variables which can be +ve or -ve...