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If 75 and 48 are divided by an integer d

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by tom4lax » Mon Sep 07, 2009 1:56 pm
Is there any easy way to calculate what d is?
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by praky_rules » Mon Sep 07, 2009 4:24 pm
lets say 75=md+15 and 48=nd+8
From the above two eqn d>15.

Now md=60=3x2x5x2
nd=40=2x2x5x2

m cannot be 1 as d will be 60 and n will be a fraction. common part between nd and md is d and d can only be(2x5x2) as this combo is greater than 15. d=20
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by tom4lax » Mon Sep 07, 2009 5:23 pm
Awesome, thanks for the explanation.
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by fruti_yum » Tue Sep 08, 2009 6:15 am
praky_rules wrote:lets say 75=md+15 and 48=nd+8
From the above two eqn d>15.

Now md=60=3x2x5x2
nd=40=2x2x5x2

m cannot be 1 as d will be 60 and n will be a fraction. common part between nd and md is d and d can only be(2x5x2) as this combo is greater than 15. d=20
praky from these two equations how to do you get that d>15?
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by Nermal » Tue Sep 08, 2009 7:32 am
They make it clear in one of the latest GMAT articles "All about Remainders", I found it very helpful:

https://www.beatthegmat.com/a/2009/09/06 ... remainders

To be honest that article enabled me to actually get an answer to this question.
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