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If 75 and 48 are divided by an integer d

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by netcaesar » Mon Sep 07, 2009 1:47 pm
If 75 and 48 are divided by an integer d they leave a remainder of 15 and 8 respectively. d could be between which of the following values?
a) 10 and 15
b) 16 and 22
c) 24 and 28
d) 28 and 32
e) 34 and 41

OA is 20, that is B
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by tom4lax » Mon Sep 07, 2009 1:56 pm
Is there any easy way to calculate what d is?
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by praky_rules » Mon Sep 07, 2009 4:24 pm
lets say 75=md+15 and 48=nd+8
From the above two eqn d>15.

Now md=60=3x2x5x2
nd=40=2x2x5x2

m cannot be 1 as d will be 60 and n will be a fraction. common part between nd and md is d and d can only be(2x5x2) as this combo is greater than 15. d=20
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by tom4lax » Mon Sep 07, 2009 5:23 pm
Awesome, thanks for the explanation.
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by fruti_yum » Tue Sep 08, 2009 6:15 am
praky_rules wrote:lets say 75=md+15 and 48=nd+8
From the above two eqn d>15.

Now md=60=3x2x5x2
nd=40=2x2x5x2

m cannot be 1 as d will be 60 and n will be a fraction. common part between nd and md is d and d can only be(2x5x2) as this combo is greater than 15. d=20
praky from these two equations how to do you get that d>15?
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by Nermal » Tue Sep 08, 2009 7:32 am
They make it clear in one of the latest GMAT articles "All about Remainders", I found it very helpful:

https://www.beatthegmat.com/a/2009/09/06 ... remainders

To be honest that article enabled me to actually get an answer to this question.
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