300! is divisible by (24!)^n. what is the max. possible integral value of n?
a .13
b.12
c. 15
d.14
e.23
a .13
b.12
c. 15
d.14
e.23
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But 23 *13 = 299liferocks wrote:greatest prime factor of 24! is 23
so number of 23 in 300! will determine the number of 24! in 300!
this is (300/23)=12
Ans option B
There u r !! Correct!liferocks wrote:greatest prime factor of 24! is 23
so number of 23 in 300! will determine the number of 24! in 300!
this is (300/23)=12
Ans option B
yup..should be 13..edited.kstv wrote:But 23 *13 = 299liferocks wrote:greatest prime factor of 24! is 23
so number of 23 in 300! will determine the number of 24! in 300!
this is (300/23)=12
Ans option B
300 will contain way more of the smaller prime factors. Thus, the number of times the greatest prime factor (of 24) can go into 300 will limit the number of times 24! can go into 300!vinay89 wrote:so number of 23 in 300! will determine the number of 24! in 300!
Dont really get why we look for the greatest prime factor?