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Master | Next Rank: 500 Posts
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by winniethepooh » Mon Jul 11, 2011 8:29 am
The center of the circle is at point (0,6). If the distance between the two points
where the circle intersects the x-axis is 16, what is the area of the circle?

This question had been decided just a few days back. I didn't quiet understand the explanations so reposted it.
Please help.
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by testprepDublin » Mon Jul 11, 2011 8:51 am
The distance between each intersection point and the centre of the circle is the radius of the circle. Since the two intersection points must be at equal length from the y-axis, the intersection points are (-8, 0) and (8,0).

The distance between one of these points and the centre is = √(8^2+6^2)=√100 = 10 = the radius

Area = πr^2 = 100π.
Deirdre at testprepdublin.com
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by winniethepooh » Mon Jul 11, 2011 8:59 am
Hey Deirdre, thanks for your reply, I really appreciate it!
Actually, I misinterpreted the words in the question!
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by MBA.Aspirant » Tue Jul 12, 2011 4:35 am
100 TT FTW
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