The center of the circle is at point (0,6). If the distance between the two points
where the circle intersects the x-axis is 16, what is the area of the circle?
This question had been decided just a few days back. I didn't quiet understand the explanations so reposted it.
Please help.
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Help please!
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winniethepooh
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testprepDublin
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The distance between each intersection point and the centre of the circle is the radius of the circle. Since the two intersection points must be at equal length from the y-axis, the intersection points are (-8, 0) and (8,0).
The distance between one of these points and the centre is = √(8^2+6^2)=√100 = 10 = the radius
Area = πr^2 = 100π.
The distance between one of these points and the centre is = √(8^2+6^2)=√100 = 10 = the radius
Area = πr^2 = 100π.
Deirdre at testprepdublin.com
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winniethepooh
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Hey Deirdre, thanks for your reply, I really appreciate it!
Actually, I misinterpreted the words in the question!
Actually, I misinterpreted the words in the question!
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MBA.Aspirant
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