the sum of three prime nos is 100 one of them exceeds the other by 36 then one of the no is:
1. 3 : sorry edited
2. 7
3. 19
4.41
5. 67
prime
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a + b + c = 100
As said above one of the prime number needs to be 2.
2 + b + c = 100
b + c = 98 ... (1)
We know the difference between b and c is 36.
c - b = 36 ... (2)
(1) - (2) ... 2b = 62 => b = 31
c = 36 + 31 = 67 - Answer: 5
As said above one of the prime number needs to be 2.
2 + b + c = 100
b + c = 98 ... (1)
We know the difference between b and c is 36.
c - b = 36 ... (2)
(1) - (2) ... 2b = 62 => b = 31
c = 36 + 31 = 67 - Answer: 5
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E
numbers are 2, 31 and 67
can get that by solving the below two equations:
a+b = 98
a-b = 36
numbers are 2, 31 and 67
can get that by solving the below two equations:
a+b = 98
a-b = 36
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