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kanha81
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q: Mach. X & Y prod. identical bottles at different constant rates. Mach. X, operating alone for 4 hrs, filled part of the produciton lot; then Mach. Y, operating alone for 3 hrs, filled the rest of lot. how many hrs would it have taken Mach. X operating alone to fill entire production lot?
i) Mach. X produces 30 bottles per min.
ii) Mach X produced twice as many bottles in 4 hrs as Mach. Y produced in 3 hrs.
Is there a simpler way of finding this out than doing the following?
let r(x): rate of Mach. X => r(x)*4=W(x)
r(y): rate of Mach. Y => r(y)*3=W(y)
r(x) <> r(y); t(x)=?
i) r(x)=30 bottles per min
=> W(x)=30*4*60= 7200 bottles
=> Insuff. b/c no information given about entire production lot or relationship between r(x) & r(y)
B,C,E
ii) r(x)=2*r(y)
Total # bottles=W(x) + W(y)=4*r(x) + 3*r(y)=5.5*r(x)
t(x)=5.5*r(x) / r(x) = 5.5 hrs.
=> Suff.
i) Mach. X produces 30 bottles per min.
ii) Mach X produced twice as many bottles in 4 hrs as Mach. Y produced in 3 hrs.
Is there a simpler way of finding this out than doing the following?
let r(x): rate of Mach. X => r(x)*4=W(x)
r(y): rate of Mach. Y => r(y)*3=W(y)
r(x) <> r(y); t(x)=?
i) r(x)=30 bottles per min
=> W(x)=30*4*60= 7200 bottles
=> Insuff. b/c no information given about entire production lot or relationship between r(x) & r(y)
B,C,E
ii) r(x)=2*r(y)
Total # bottles=W(x) + W(y)=4*r(x) + 3*r(y)=5.5*r(x)
t(x)=5.5*r(x) / r(x) = 5.5 hrs.
=> Suff.
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