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by shankar.ashwin » Mon Sep 26, 2011 4:33 am
total 20 terms.

Median = (10th term + 11th term)/2 [Even No of terms]

= (84+84)/2 = 84
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by Anurag@Gurome » Mon Sep 26, 2011 4:39 am
gunjan1208 wrote:Can somebody help me posting the explanation please?
If there are odd # of terms, then the median of a set of numbers is the middle term and if there are even # of terms then the median is the average of the two middle terms.

Here the set has 20 terms (even # of terms), so the median will be the average of the 10th and 11th terms.

Now arrange the terms in increasing order, we see that the first 3 terms, 48, 70, 80, account for 9 of the 20 terms. Therefore, the 10th and 11th terms in the set will both be 84, so the median will also be 84.

The correct answer is B.
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by gunjan1208 » Wed Sep 28, 2011 1:53 am
Anurag,

Thank you so very much. I never imagined I could ask such an easy question on the forum. But I got this wrong on diagnostic and I could not even guess later.

Regards
Gunjan
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