Machine A produces bolts at a uniform rate of 120 every 40

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Machine A produces bolts at a uniform rate of 120 every 40 seconds, and Machine B produces bolts at a uniform rate of 100 every 20 seconds. If the two machines run simultaneously, how many seconds will it take for them to produce a total of 200 bolts?

A. 22
B. 25
C. 28
D. 32
E. 56

The OA is B.

Is there a strategic approach to solve this question? Can anyone help? Thanks!

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by [email protected] » Wed Jul 04, 2018 1:31 pm
Hi All,

We're told that Machine A produces bolts at a uniform rate of 120 every 40 seconds and Machine B produces bolts at a uniform rate of 100 every 20 seconds. We're asked if the two machines run simultaneously, how many seconds will it take for them to produce a total of 200 bolts. The 'math' behind this question can be approached in a number of different ways. Since the Machines produce bolts in 'nice, round' numbers, we can calculate the number of bolts that each machine produces per second.

Machine A produces 120 bolts every 40 seconds, so that's 120/40 = 3 bolts/second.
Machine A produces 100 bolts every 20 seconds, so that's 100/20 = 5 bolts/second.
Total = 8 bolts/second

The time it would take to produce 200 bolts would be 200/8 = 25 seconds.

Final Answer: B

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by Scott@TargetTestPrep » Sun Jul 22, 2018 5:42 pm
AAPL wrote:Machine A produces bolts at a uniform rate of 120 every 40 seconds, and Machine B produces bolts at a uniform rate of 100 every 20 seconds. If the two machines run simultaneously, how many seconds will it take for them to produce a total of 200 bolts?

A. 22
B. 25
C. 28
D. 32
E. 56
We are given that machine A produces bolts at a uniform rate of 120 every 40 seconds. Thus, the rate of Machine A is 120/40 = 3 bolts/second.

We are also given that Machine B produces bolts at a uniform rate of 100 every 20 seconds. Thus, the rate of Machine B is 100/20 = 5 bolts/second.

We need to determine the time it will take to produce 200 bolts when the two machines run simultaneously.

To determine the time to produce 200 bolts, we can use the combined work formula:

Work by Machine A + Work by Machine B = 200 bolts (the total work completed).

Because both machines are working simultaneously, we can say that they both work together for t seconds. We now can express the individual work done by Machine A and by Machine B. We must remember that work = rate x time.

Work done by Machine A = 3t

Work done by Machine B = 5t

3t + 5t = 200

8t = 200

t = 200/8 = 25

Alternate Solution:

Since Machine A produces 120 bolts every 40 seconds, it will produce 60 bolts every 20 seconds. Combined with Machine B, the two machines will produce 100 + 60 = 160 bolts every 20 seconds. To find the time it will take the two machines to produce 200 bolts, we can set up a simple proportion: "160 bolts is to 20 seconds as 200 bolts is to t seconds"

160/20 = 200/t

t = (200 x 20)/160 = 25 seconds

Answer: B

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