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A room contains

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by amitabhprasad » Tue Dec 23, 2008 6:14 pm
A room contains 160 people, 15% of whom are women. A group of people, 30% of whom are women, leaves the room. Of the people remaining in the room, 10% are women. How many people left the room?


A-10
B-20
C-40
D-60
E-80

I don't have official answer but this is what I am getting C wanted to check with you guys
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Source: — Problem Solving |

Re: A room contains

by Ossa » Tue Dec 23, 2008 6:49 pm
Hi,

If we choose answer C: 40 people left the room. 30% were women, so 12 women left.
We know that originally there were 24 women in the room, and after 40 leave, 120 remain, 12 of them are women, which is 10%.

amitabhprasad wrote:A room contains 160 people, 15% of whom are women. A group of people, 30% of whom are women, leaves the room. Of the people remaining in the room, 10% are women. How many people left the room?


A-10
B-20
C-40
D-60
E-80

I don't have official answer but this is what I am getting C wanted to check with you guys
Ossa Elhadary, PhD, CISA, PMP
Math Specialist
Test Prep New York
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www.testprepny.com
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by parallel_chase » Tue Dec 23, 2008 8:36 pm
Total female

160*15% = 24

let x people leave the room

x*30% = female

out of people left in the room

(160-x)10% = female


We just have to find the value of x

(160-x)10% + x*30% = 24

160 - x + 3x = 240

160 + 2x = 240

2x = 80

x = 40

Hence C.
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by ronniecoleman » Tue Dec 23, 2008 11:17 pm
Yup IMO C
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by cramya » Tue Dec 23, 2008 11:27 pm
15% of 160 are women = 24

Let x represent people who left the room(30% of these are women + 10% of 160-x are women and these both must add up to the original number of women we found above i.e. 24)

.30x + .10(160-x) = 24

x=40
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