Vincen wrote: ↑Tue Jan 05, 2021 3:28 am
\(M\) is the sum of the reciprocals of the consecutive integers from \(201\) to \(300,\) inclusive. Which of the following is true?
(A) \(\dfrac13 < M < \dfrac12\)
(B) \(\dfrac15 < M < \dfrac13\)
(C) \(\dfrac17 < M < \dfrac15\)
(D) \(\dfrac19 < M < \dfrac17\)
(E) \(\dfrac1{12} < M < \dfrac19\)
Answer:
A
Source: Official Guide
We want to find 1/201 + 1/202 + 1/203 + . . . + 1/299 + 1/300
NOTE: there are 100 fractions in this sum.
Let's examine the extreme values (1/201 and 1/300)
First consider a case where all of the values are equal to the
smallest fraction (1/300)
We get: 1/300 + 1/300 + 1/300 + ... + 1/300 = 100/300 = 1/3
So, the original sum must be
greater than 1/3
Now consider a case where all of the values are equal to the
biggest fraction (1/201)
In fact, let's go a little bigger and use 1/200
We get: 1/200 + 1/200 + 1/200 + ... + 1/200 = 100/200 = 1/2
So, the original sum must be
less than 1/2
Combine both cases to get
1/3 < M <
1/2
Answer: A
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
