Problem Solving

In a particular card game, odd-numbered cards are assigned a value of 2, even numbered cards a value of 3, and face cards and aces a value of 7. Each player draws x number of cards per round and multiplies the resulting point values together. If a player's score is 2,058 after the first round, what could be the value of x?

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2058 is same as 2*3*7^3

Since the multiplication of card values is some combination of 2, 3 and 7 - the only way the product would be 2058 is when there are 7 cards with value 7 and one card each with value 2 and 3, so a total of 5 cards - Answer B

beyondgmatscore wrote:2058 is same as 2*3*7^3

Since the multiplication of card values is some combination of 2, 3 and 7 - the only way the product would be 2058 is when there are 7 cards with value 7 and one card each with value 2 and 3, so a total of 5 cards - Answer B

i think you tried to write 3 cards with value 7

@ Blaster:You can't have any other answer.
All the numbers are primes!

Yes - I did mean to write 3 cards with value 7 each. Thanks for pointing this out.

blaster wrote:

beyondgmatscore wrote:2058 is same as 2*3*7^3

Since the multiplication of card values is some combination of 2, 3 and 7 - the only way the product would be 2058 is when there are 7 cards with value 7 and one card each with value 2 and 3, so a total of 5 cards - Answer B

i think you tried to write 3 cards with value 7

Yepp, it is B.
Took 4 mins to figure it out!

A, Queen , King , Jack category card = 3 ( 7 face value)
odd numbered card= 1
even numbered card = 1