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by finance » Thu Jul 21, 2011 2:41 am
In a particular card game, odd-numbered cards are assigned a value of 2, even numbered cards a value of 3, and face cards and aces a value of 7. Each player draws x number of cards per round and multiplies the resulting point values together. If a player’s score is 2,058 after the first round, what could be the value of x?

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by beyondgmatscore » Thu Jul 21, 2011 3:22 am
2058 is same as 2*3*7^3

Since the multiplication of card values is some combination of 2, 3 and 7 - the only way the product would be 2058 is when there are 7 cards with value 7 and one card each with value 2 and 3, so a total of 5 cards - Answer B
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by blaster » Sun Jul 24, 2011 9:41 pm
beyondgmatscore wrote:2058 is same as 2*3*7^3

Since the multiplication of card values is some combination of 2, 3 and 7 - the only way the product would be 2058 is when there are 7 cards with value 7 and one card each with value 2 and 3, so a total of 5 cards - Answer B
i think you tried to write 3 cards with value 7
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by winniethepooh » Sun Jul 24, 2011 10:05 pm
@ Blaster:You can't have any other answer.
All the numbers are primes!
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by beyondgmatscore » Sun Jul 24, 2011 11:14 pm
Yes - I did mean to write 3 cards with value 7 each. Thanks for pointing this out.
blaster wrote:
beyondgmatscore wrote:2058 is same as 2*3*7^3

Since the multiplication of card values is some combination of 2, 3 and 7 - the only way the product would be 2058 is when there are 7 cards with value 7 and one card each with value 2 and 3, so a total of 5 cards - Answer B
i think you tried to write 3 cards with value 7
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by Ozlemg » Mon Jul 25, 2011 3:03 am
Yepp, it is B.
Took 4 mins to figure it out!
The more you suffer before the test, the less you will do so in the test! :)
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by navami » Mon Jul 25, 2011 6:57 am
A, Queen , King , Jack category card = 3 ( 7 face value)
odd numbered card= 1
even numbered card = 1
This time no looking back!!!
Navami
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