Vincen wrote: ↑

Tue Apr 28, 2020 7:33 am

Louie takes out a three-month loan of $1000. The lender charges him 10% interest per month compounded monthly. The terms of the loan state that Louie must repay the loan in three equal monthly payments. To the nearest dollar, how much does Louie have to pay each month?

A)333
B)383
C)402
D)433
E)483

[spoiler]OA=C[/spoiler]

Source: GMAT Prep

Say the monthly equated payment be $x.

Thus,

After the first month, ${(1,000*1.1) – x} is left to pay;
After the second month, $[{(1,000*1.1) – x}*1.1 – x] = $(1,210 – 2.1x) is left to pay;

Thus, the last installment, x = $(1,210 – 2.1x)*1.1

x = 1,331/331 = ~$402

The correct answer: C

Hope this helps!

-Jay
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Vincen wrote: ↑

Tue Apr 28, 2020 7:33 am

Louie takes out a three-month loan of $1000. The lender charges him 10% interest per month compounded monthly. The terms of the loan state that Louie must repay the loan in three equal monthly payments. To the nearest dollar, how much does Louie have to pay each month?

A)333
B)383
C)402
D)433
E)483

[spoiler]OA=C[/spoiler]

Source: GMAT Prep

We can let p be his monthly payment.

At the end of the first month, the loan will accrue 0.1(1000) = 100 dollars of interest, and the total amount is $1100. Since he will make a payment of p dollars , he has (1100 - p) dollars left to pay.

At the end of the second month, the loan will accrue 0.1(1100 - p) dollars of interest, and the total amount is 1.1(1100 - p) dollars. Since he will make a payment of p dollars, he has 1.1(1100 - p) - p = (1210 - 2.1p) dollars left to pay.

At the end of the third month, the loan will accrue 0.1(1210 - 2.1p) dollars of interest, and the total amount is 1.1(1210 - 2.1p) dollars. Since he will make a payment of p dollars, he has 1.1(1210 - 2.1p) - p = 1331 - 3.31p dollars left to pay. However, since we know that he will pay off this loan in 3 months, it must be true that what he has left to pay is $0. That is,

1331 - 3.31p = 0

1331 = 3.31p

p = 1331/3.31 ≈ 402

Answer: C