Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

looking for a faster way

Expert replies
by tony777 » Wed Mar 19, 2008 9:13 pm
I thought this question was a simple one but I spent a ridiculous amount of time working through to an answer.

Any tips out there on how to approach it.

An agent was billed a total of $6.00 for n reams of paper. As a result of a price increase of $0.25 per ream, the agents next bill of $6.00 was for 4 fewer reams of paper. The second bill was for how many reams of paper?

(A) 8
(B) 12
(C) 24
(D) 25
(E) 48
Join the discussion
Source: — Problem Solving |

Re: looking for a faster way

by aarunibens » Wed Mar 19, 2008 10:30 pm
n reams = $ 6
1 ream = $ 6 / n

if price is increased by $ 0.25 / ream, the new price per ream =

6/n + 0.25

now, for n-4 reams, the price = $ 6

hence price per ream = 6 / (n-4)

6 / (n-4) = 6/n + 0.25

Solve the above equation and find the value of (n-4). That would be the answer.[/quote][/spoiler]
Join the discussion

by tony777 » Thu Mar 20, 2008 12:15 am
Thanks, I like your set up, but to solve that equation still seems to take a long time, this is how i went about it.

6/(n-4) = 6/n + 0.25
6/(n-4) - 6/n = 0.25
(6n-6n+24)/(n^2-4n) = 0.25 (adding the 1st half fractions together)
24 = (n^2-4n)x0.25
24/0.25=n^2-4n
n^2-4n-96=0
(n+8)(n-12)
n=-8, n=12 (disregard n=-8 because its not logical for this problem)
n-4 = 8
The answer is A

Does anyone have a faster way?
Join the discussion

by xilef » Thu Mar 20, 2008 10:01 am
I got the following 2 equations:

x - cost per ream

nx=6
(x+1/4)(n-4)=6

solving for x:

(x+1/4)(6/x-4)=6
6-4x+3/2x-1=6
10x-8x^2+6x=12x multiply everything by 2x
0=8x^2-4x
0=2x^2-x
x=0 or x=1/2

x=1/2 and n = 12

the answer is n-4=12-4=8


The problem is simple but the calculation can be tricky. I guess you can try plugging in the answers once you have the equations setup. Since in this problem the correct answer is A, you would save a lot of time.
Join the discussion

Re: looking for a faster way

by Stuart@KaplanGMAT » Thu Mar 20, 2008 12:41 pm
tony777 wrote:I thought this question was a simple one but I spent a ridiculous amount of time working through to an answer.

Any tips out there on how to approach it.

An agent was billed a total of $6.00 for n reams of paper. As a result of a price increase of $0.25 per ream, the agents next bill of $6.00 was for 4 fewer reams of paper. The second bill was for how many reams of paper?

(A) 8
(B) 12
(C) 24
(D) 25
(E) 48
Backsolving time!

When we have a complicated word problem and answers that are actual numbers (as opposed to, e.g., variables), working backward from the answers can be a great way to attack the question (and avoid the algebra).

Using the Kaplan method for backsolving, we start by quickly scanning the choices to see if any just don't make sense. In this particular case, we can actually eliminate 4 of the 5 choices!

We know that the answer is 4 reams fewer than the original number. If we jot down the original numbers beside the answers, we get:

(A) 8 12
(B) 12 16
(C) 24 28
(D) 25 29
(E) 48 52

Since the amount spent is $6.00, we know that both the original number and the new number MUST go into $6.00. Of all the choices, only (A) has two numbers that BOTH go into $6.00 - therefore, (A) must be the right answer.

* * *

Let's say, for the sake of the exercise, that we weren't able to use our advanced Kap-fu and figure out that only (A) makes sense. In that case, we'd actually go through the backsolving process, starting with either (B) or (D). Since (B) is a simpler number, let's begin there.

First, we assume that (B) is the right answer.

So, if the new # of reams is 12, then new price/ream is 6.00/12 = 50 cents.

Further, if the new # of reams is 12, then the original number is 16. Therefore, the original price/ream is 6.00/16 = .. umm.. doesn't work, but to estimate: 37ish cents.

Now, let's look at the difference: 50 cents - 37 cents = 13 cents. Does that match the story? NO - we wanted a difference of 25 cents: eliminate (B).

Next, figure out if we need a bigger or smaller number. Since we want the extra 4 reams to have a bigger impact (so we get a bigger difference), we need to REDUCE the number of reams: eliminate all the answers bigger than 12, i.e. (C), (D) and (E).

Only (A) remains - done!!
Image

Stuart Kovinsky | Kaplan GMAT Faculty | Toronto

Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
Join the discussion

Re: looking for a faster way

by HarvardDreamin » Fri Mar 21, 2008 9:21 am
tony777 wrote:I thought this question was a simple one but I spent a ridiculous amount of time working through to an answer.

Any tips out there on how to approach it.

An agent was billed a total of $6.00 for n reams of paper. As a result of a price increase of $0.25 per ream, the agents next bill of $6.00 was for 4 fewer reams of paper. The second bill was for how many reams of paper?

(A) 8
(B) 12
(C) 24
(D) 25
(E) 48
before n = 6, now

1.25n-4 = 6,
1.25 = 10
n=8
ON MY WAY TO HBS......
Join the discussion

by xilef » Fri Mar 21, 2008 9:47 am
HarvardDreamin,
n was not 6 before, n reams cost 6$.

This solution does not make sense. The fact that you also got 8 is a coincidence.
Join the discussion

by HarvardDreamin » Fri Mar 21, 2008 11:49 am
xilef wrote:HarvardDreamin,
n was not 6 before, n reams cost 6$.

This solution does not make sense. The fact that you also got 8 is a coincidence.
Before, the no of reams * price of reams = N

Hence using mathematical logic + info provided, it leads to the second equation:

"1.25n-4 = 6"

which when solved gives the right answer. I understand that this solution relies on my intuition and logic but I find it hard to understand how it could be a coincidence given the most important equation above is correct.
ON MY WAY TO HBS......
Join the discussion

by xilef » Fri Mar 21, 2008 12:42 pm
1.25n-4 = 6

You are multiplying the number of reams by 1.25, the price per ream was increased by 25 cents not 25% and then you are subtracting 4 reams from that and you get the total price for all reams. Can you explain your logic, because to me it seems to be off?
Join the discussion