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GMATPrep DS Q

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GMATPrep DS Q

by bodyoflies » Sun Nov 09, 2008 12:49 pm
Please explain your answer, Thanks!
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Re: GMATPrep DS Q

by logitech » Sun Nov 09, 2008 1:34 pm
bodyoflies wrote:Please explain your answer, Thanks!
1) x-3 = y ; x=3+y insuf we dont know Y
2) x-3 = must be positive = -y is negative for any Y , so it is 0

x-3=0

x=3

SUF

B
LGTCH
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by Fab » Sun Nov 09, 2008 6:23 pm
Hey Logitech, could you please explain...?

THANKS.
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by cramya » Sun Nov 09, 2008 6:56 pm
Stmt I

|x-3| >=y (This bascially means that the distance of x from 3 is greater than or equal to y)

x could be 4,5,2,1 (just to list a few)anything to satisfy this inequality
(leading to indefinite set of values for x)

INSUFF

Stmt II
|x-3| <=-y

Since y is positive -y will be negative. The aboslute value can never be negative so to satisy the equation above y has to be zero which means
|x-3| has to be 0 (lowest value an absolute value expression can take)

i.e. x-3 = 0
x=3

SUFF

B)

Hope this helps! Let me know if u still have questions
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by logitech » Sun Nov 09, 2008 7:19 pm
Cramya does the explaining and being nice part, I just solve the questions.

That's how I roll! :twisted:
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by cramya » Sun Nov 09, 2008 7:38 pm
Cant get away with that lame explanation, Logitech :-)
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