jackcrystal wrote:E ? Surprise!!!

question stem: d1/r1 > d2/r2 Statement I and II are clearly insufficient. In statement I r1 & r2 can be same numbers or different numbers. Therefore we can have both cases, smaller & greater. Insufficient. Similarly In statement II d1 & d2 can be same numbers or different numbers. Insufficient. Combining I & II let d2=1, d1=31 let r2=1, r1=31 d1/r1 > d2/r2 31/31 > 1/1 1>1--------------------NO let d2=10, d1=40 let r2=15, r1=45 d1/r1 > d2/r2 40/10 > 45/15 4>3---------------------YES Insufficient. Hence E.

parallel_chase wrote:question stem: d1/r1 > d2/r2 Statement I and II are clearly insufficient. In statement I r1 & r2 can be same numbers or different numbers. Therefore we can have both cases, smaller & greater. Insufficient. Similarly In statement II d1 & d2 can be same numbers or different numbers. Insufficient. Combining I & II let d2=1, d1=31 let r2=1, r1=31 d1/r1 > d2/r2 31/31 > 1/1 1>1--------------------NO let d2=10, d1=40 let r2=15, r1=45 d1/r1 > d2/r2 40/10 > 45/15 4>3---------------------YES Insufficient. Hence E. d1/r1 > d2/r2 (d1/r1) - (d2/r2) > 0 d1r2-d2r1 / (r1r2) > 0 we know that r1r2 is positive so it boils down to whether d1r2 > d2r1

Slightly different procedure clearly I and II alone are insufficient we have to find whether d1/r1 > d2/r2 given from I: d1=d2 + 30 from II: r1 = r2 + 30 d1/r1 = (d2 + 30) / (r2 + 30) muliply and divide by r2 = (d2r2 + 30r2)/(r2*(r2+30)) d2/r2 = mutiply and divide by (r2+30) (d2r2 + 30d2)/(r2*(r2+30)) now we have to compare the numerators of the fractions d2r2 + 30r2 > d2r2 + 30d2 so it boils down to the comparision between d2 and r2...................or (d1 and r1) we dont have any info on this ......so E