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Logitech DS3
Source: Beat The GMAT — Data Sufficiency |
-
jackcrystal
- Senior | Next Rank: 100 Posts
- Posts: 31
- Thanked: 1 times
question stem: d1/r1 > d2/r2
Statement I and II are clearly insufficient.
In statement I r1 & r2 can be same numbers or different numbers. Therefore we can have both cases, smaller & greater. Insufficient.
Similarly In statement II d1 & d2 can be same numbers or different numbers. Insufficient.
Combining I & II
let d2=1, d1=31
let r2=1, r1=31
d1/r1 > d2/r2
31/31 > 1/1
1>1--------------------NO
let d2=10, d1=40
let r2=15, r1=45
d1/r1 > d2/r2
40/10 > 45/15
4>3---------------------YES
Insufficient.
Hence E.
Statement I and II are clearly insufficient.
In statement I r1 & r2 can be same numbers or different numbers. Therefore we can have both cases, smaller & greater. Insufficient.
Similarly In statement II d1 & d2 can be same numbers or different numbers. Insufficient.
Combining I & II
let d2=1, d1=31
let r2=1, r1=31
d1/r1 > d2/r2
31/31 > 1/1
1>1--------------------NO
let d2=10, d1=40
let r2=15, r1=45
d1/r1 > d2/r2
40/10 > 45/15
4>3---------------------YES
Insufficient.
Hence E.
No rest for the Wicked....
d1/r1 > d2/r2parallel_chase wrote:question stem: d1/r1 > d2/r2
Statement I and II are clearly insufficient.
In statement I r1 & r2 can be same numbers or different numbers. Therefore we can have both cases, smaller & greater. Insufficient.
Similarly In statement II d1 & d2 can be same numbers or different numbers. Insufficient.
Combining I & II
let d2=1, d1=31
let r2=1, r1=31
d1/r1 > d2/r2
31/31 > 1/1
1>1--------------------NO
let d2=10, d1=40
let r2=15, r1=45
d1/r1 > d2/r2
40/10 > 45/15
4>3---------------------YES
Insufficient.
Hence E.
(d1/r1) - (d2/r2) > 0
d1r2-d2r1 / (r1r2) > 0
we know that r1r2 is positive
so it boils down to whether d1r2 > d2r1
LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
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"DON'T LET ANYONE STEAL YOUR DREAM!"
Slightly different procedure
clearly I and II alone are insufficient
we have to find whether d1/r1 > d2/r2
given from I: d1=d2 + 30
from II: r1 = r2 + 30
d1/r1 = (d2 + 30) / (r2 + 30)
muliply and divide by r2 = (d2r2 + 30r2)/(r2*(r2+30))
d2/r2 = mutiply and divide by (r2+30)
(d2r2 + 30d2)/(r2*(r2+30))
now we have to compare the numerators of the fractions
d2r2 + 30r2 > d2r2 + 30d2
so it boils down to the comparision between
d2 and r2...................or (d1 and r1)
we dont have any info on this ......so E
clearly I and II alone are insufficient
we have to find whether d1/r1 > d2/r2
given from I: d1=d2 + 30
from II: r1 = r2 + 30
d1/r1 = (d2 + 30) / (r2 + 30)
muliply and divide by r2 = (d2r2 + 30r2)/(r2*(r2+30))
d2/r2 = mutiply and divide by (r2+30)
(d2r2 + 30d2)/(r2*(r2+30))
now we have to compare the numerators of the fractions
d2r2 + 30r2 > d2r2 + 30d2
so it boils down to the comparision between
d2 and r2...................or (d1 and r1)
we dont have any info on this ......so E
