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Local Trade show problem

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by sanjana » Sat Oct 03, 2009 10:10 pm
During a 6 day local trade show,the least number of people registered in a single day was 80.Was the Avg(arithemetic mean) number of ppl registered per day for the 6 days greater than 90?

a)For the 4 days with the greatest number of ppl registered,the avg(arithemetic mean) number registered per day was 100.

b)For the 3 days with the smallest number of ppl registered,the avg number registered per day was 85
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Source: — Data Sufficiency |

by catchyblues » Sun Oct 04, 2009 7:30 am
IMO A

1) Out of 6 days, 4 days had avg number registered per day = 100

That makes 400 for 4 days. Adding 80 to will give us 480. Even by considering the 6th day as 80 or 81, the average for 6 days will be greater that 90.

2)For the 3 days with the smallest number of ppl registered,the avg number registered per day was 85.

So for 3 days (including the 80 from the main statement), the today for 3 days is 265. We don't have any information about the other 3 days. Even if we assume a minimum of 86 for each of the 3 days, the avg will be less than 90. If we assume 100 for each of the 3 days, the avg will be > 90. Hence we can't solve using (2).
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by sanjana » Sun Oct 04, 2009 8:12 pm
Thanks!
The OA is A.
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