Is the integer n odd?
(1) n is divisible by 3.
(2) 2n is divisible by twice as many positive integers as n.
OA is B.
(1) n is divisible by 3.
(2) 2n is divisible by twice as many positive integers as n.
OA is B.
1) n could be 3, which is odd and divisible by 3, but it could also be 6, which is even and divisible by 3. Insufficient.
2) If n is 2, its factors are 1 and 2. 2n=4, and the factors of 4 are 1, 2, and 4. 3 factors is not twice as many as 2 factors, so n can't be even. If n is 3, its factors are 1 and 3. 2n=6, and the factors of 6 are 1, 2, 3, and 6. 4 factors is twice as many as 2 factors, so n must be odd.
You could also double-check with a non-prime odd. If n=9, then its factors are 1, 3, and 9. 2n=18, and the factors of 18 are 1, 2, 3, 6, 9, and 18. 6 factors is twice as many as 3 factors.
