atulmangal wrote:Is the integer n odd?
(1) n is divisible by 3.
(2) 2n is divisible by twice as many positive integers as n.

atulmangal wrote: Hi Anurag,

Thanks a lot but i have one doubt...in this question don't u think, Op B interpret something else than what u interpret...actually this is why i was not able to solve this question..

Op B: 2n is divisible by twice as many positive integers as n

i interpret it as "2n" is divisible by "2n" numbers---> this is nonsensical but this is what the language of Op B suggest...m i wrong ???

sourabh33 wrote:Hi Anurag

A small clarification to be made

If n = 6 (Even), then 2n = 12; n is divisible by 1,2,3 & 6....while 2n is divisible by 1,2,3,4,6 and 12. Here, 2n has twice as many divisors as n, so even statement B should be insufficient.

Now, taking 1&2 together, if we choose 3 and 6 as test numbers both qualify in statements 1 & 2. So the answer should be E




In addition, if we consider Atul's interpretation to be correct (although I do not agree with that)
then for statement 2 to be true, n has to be 1.

If n = 1 (odd), then 2n = 2; n is divisible by only 1....while 2n is divisible by 1 and 2. Here, 2n has twice as many divisors as n, so only in this case B could be sufficient.

Please clarify

Best Regards
Sourabh