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Length based on prime factor

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by bharatv » Sat May 16, 2009 11:13 pm
For any positive integer n, the length of n is defined as the number of prime factors whose product is n. For example, the length of 75 is 3, since 75 = 3 x 5 x 5. How many two-digit positive integers have length 6?

a. none
b. one
c. two
d. three
e. four

Can any one explain on this please.?
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by dumb.doofus » Sat May 16, 2009 11:28 pm
I think there's jsut two 64 and 96 (post edited)
Last edited by dumb.doofus on Sun May 17, 2009 12:33 am, edited 1 time in total.
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by bharatv » Sat May 16, 2009 11:40 pm
The OA seems to be C(Two)

But how did you calculate. Is there a easy way to do this?
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by scoobydooby » Sun May 17, 2009 12:28 am
figured out the other: 96 :)

2^5*3=96
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by dumb.doofus » Sun May 17, 2009 12:32 am
yeah :-) missed out on this one. ;-)

I don't see a simpler way other than just checking it manually..
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