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leaves the same remainder

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by GoMBA » Tue Aug 19, 2008 8:23 am
Can someone help with a technique to solve this and similar type questions....

Find the greatest number, which will divide 215,167 and 135 so as to leave the same remainder in each case?

a. 64
b. 32
c. 24
d. 16
e. 8
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Re: leaves the same remainder

by sudhir3127 » Tue Aug 19, 2008 8:37 am
GoMBA wrote:Can someone help with a technique to solve this and similar type questions....

Find the greatest number, which will divide 215,167 and 135 so as to leave the same remainder in each case?

a. 64
b. 32
c. 24
d. 16
e. 8
My answer is D. 16i hope i will be a help:)

the technique is to understand the question .. the "greatest number " u need to find the GCD of mod ( c-a),mod ( a-b), mod ( b-c) thats it ..

hence the numbers are 80, 32,48.

GCD of them is 16. thats it ...

If he asks u the least number .. then do an LCM...

do let me know if u have any doubts,,,
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Re: leaves the same remainder

by GoMBA » Tue Aug 19, 2008 8:44 am
Taking the GCD because its asking for the greatest number is something i was also able to guess. But how did you arrive at taking the GCD for (c-a), (a-b), (b-c)? And also i didnt understand what do you mean by mod(c-a)?

Thanks.


sudhir3127 wrote:
GoMBA wrote:Can someone help with a technique to solve this and similar type questions....

Find the greatest number, which will divide 215,167 and 135 so as to leave the same remainder in each case?

a. 64
b. 32
c. 24
d. 16
e. 8
My answer is D. 16i hope i will be a help:)

the technique is to understand the question .. the "greatest number " u need to find the GCD of mod ( c-a),mod ( a-b), mod ( b-c) thats it ..

hence the numbers are 80, 32,48.

GCD of them is 16. thats it ...

If he asks u the least number .. then do an LCM...

do let me know if u have any doubts,,,
Top
Join the discussion
Legendary Member
Posts: 829
Joined: Mon Jul 07, 2008 10:09 pmFollowed by: 3 members
Location: INDIA
Thanked: 84 times

Re: leaves the same remainder

by sudhir3127 » Tue Aug 19, 2008 8:49 am
GoMBA wrote:Taking the GCD because its asking for the greatest number is something i was also able to guess. But how did you arrive at taking the GCD for (c-a), (a-b), (b-c)? And also i didnt understand what do you mean by mod(c-a)?

Thanks.



sudhir3127 wrote:
GoMBA wrote:Can someone help with a technique to solve this and similar type questions....

Find the greatest number, which will divide 215,167 and 135 so as to leave the same remainder in each case?

a. 64
b. 32
c. 24
d. 16
e. 8
My answer is D. 16i hope i will be a help:)

the technique is to understand the question .. the "greatest number " u need to find the GCD of mod ( c-a),mod ( a-b), mod ( b-c) thats it ..

hence the numbers are 80, 32,48.

GCD of them is 16. thats it ...

If he asks u the least number .. then do an LCM...

do let me know if u have any doubts,,,

I am sorrie abt that.. Mod mean Absolute.. thats the formula...
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by 4meonly » Thu Aug 21, 2008 7:13 am
why we should find GCD of the difference?
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by Ian Stewart » Thu Aug 21, 2008 8:10 am
If we write out what the question is saying, where d is the divisor, and r the remainder, we have:

1. 215 = ad + r
2. 167 = bd + r
3. 135 = cd + r

If you subtract these in pairs (subtract 2. from 1., 3. from 2., and 3. from 1.) we have:

48 = (a-b)d
32 = (b-c)d
80 = (a-c)d

That is, 48, 32 and 80 are all multiples of d. The largest possible value of d is the GCD of 48, 32 and 80, which is 16.
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

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