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Start the planA) 1
B) 2
C) 3
D) 4
E) 5
OAB
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Start the plan|a-b| = the DISTANCE between a and b.If y is an integer, then the least possible value of |23-5y| is
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
To minimize |23-5y|, we need to find the value of y such that 23-5y is as close to zero as possible.If y is an integer, then the least possible value of |23 - 5y| is
A) 1
B) 2
C) 3
D) 4
E) 5
Can you please clarify the line of reasoning?We can just test each answer choice:
A) 1. So, |23 - 5y| = |23 - 5(1)| = 18
B) 2. So, |23 - 5y| = |23 - 5(2)| = 13
C) 3. So, |23 - 5y| = |23 - 5(3)| = 8
D) 4. So, |23 - 5y| = |23 - 5(4)| = 3
E) 5. So, |23 - 5y| = |23 - 5(5)| = 2
So, when y = 5, |23 - 5y| = |23 - 5(5)| = |-2| = 2 (and 2 is the smallest possible value of |23 - 5y|)
The question asks, "What is the least possible value of |23 - 5y|?
So, the least possible value of |23 - 5y| is 2 (and this occurs when y = 5)
However the least possible value of |23-5y| is not 3 but 2.A) 0, So, |23 - 5y| = |23 - 5(0)| = 23
B) 1. So, |23 - 5y| = |23 - 5(1)| = 18
C) 2. So, |23 - 5y| = |23 - 5(2)| = 13
D) 3. So, |23 - 5y| = |23 - 5(3)| = 8
E) 4. So, |23 - 5y| = |23 - 5(4)| = 3
So, when y = 4, |23 - 5y| = |23 - 5(4)| = |3| = 3 (and 3 is the smallest possible value of |23 - 5y|).
YIKES!GMATGuruNY wrote:Can you please clarify the line of reasoning?We can just test each answer choice:
A) 1. So, |23 - 5y| = |23 - 5(1)| = 18
B) 2. So, |23 - 5y| = |23 - 5(2)| = 13
C) 3. So, |23 - 5y| = |23 - 5(3)| = 8
D) 4. So, |23 - 5y| = |23 - 5(4)| = 3
E) 5. So, |23 - 5y| = |23 - 5(5)| = 2
So, when y = 5, |23 - 5y| = |23 - 5(5)| = |-2| = 2 (and 2 is the smallest possible value of |23 - 5y|)
The question asks, "What is the least possible value of |23 - 5y|?
So, the least possible value of |23 - 5y| is 2 (and this occurs when y = 5)
The answer choices represent the value of |23-5y|, but in the solution above they are being substituted for y.
If the answer choices were 0, 1, 2, 3, 4, this approach would seem to proceed as follows:
However the least possible value of |23-5y| is not 3 but 2.A) 0, So, |23 - 5y| = |23 - 5(0)| = 23
B) 1. So, |23 - 5y| = |23 - 5(1)| = 18
C) 2. So, |23 - 5y| = |23 - 5(2)| = 13
D) 3. So, |23 - 5y| = |23 - 5(3)| = 8
E) 4. So, |23 - 5y| = |23 - 5(4)| = 3
So, when y = 4, |23 - 5y| = |23 - 5(4)| = |3| = 3 (and 3 is the smallest possible value of |23 - 5y|).
rsarashi wrote:If y is an integer, then the least possible value of |23 - 5y| is
A) 1
B) 2
C) 3
D) 4
E) 5
OAB
To solve this question, we must make sure we interpret it correctly. We are not finding the least possible value of y, but rather the least possible value of |23-5y| (the absolute value of 23 – 5y). Remember that the smallest value that can result from taking the absolute value is zero. Thus we need to make 23 - 5y as close to zero as possible.rsarashi wrote:If y is an integer, then the least possible value of |23 - 5y| is
A) 1
B) 2
C) 3
D) 4
E) 5

|23-5y| is always greater than or equal to 0rsarashi wrote:If y is an integer, then the least possible value of |23 - 5y| is
A) 1
B) 2
C) 3
D) 4
E) 5
OAB
The least possible value of a number in modulus is 0.rsarashi wrote:If y is an integer, then the least possible value of |23 - 5y| is
A) 1
B) 2
C) 3
D) 4
E) 5
OAB