The solid brick shown is made of small bricks of side 1. When the large brick is disassembled into its component small bricks, the total surface area of all the small bricks is how much greater than the surface area of the large brick?
A. 32
B. 40
C. 60
D. 72
E. 80
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Large to small brick
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harsh.champ
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shashank.ism
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so dimension of bigger brick = 3x2x2harsh.champ wrote:The solid brick shown is made of small bricks of side 1. When the large brick is disassembled into its component small bricks, the total surface area of all the small bricks is how much greater than the surface area of the large brick?
A. 32
B. 40
C. 60
D. 72
E. 80
so its surface area = 2(2x2+3x2 +3x2) = 32
total surface area of single block = 2(1x1+1x1+1x1) = 6
there are total 12 bricks smaller one
so total surface area = 12x 6 = 72
[spoiler]so diff= 72 -32 = 40 Ans B[/spoiler]
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gmattarget700
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I think Question should be corrected: instead of asking "how much greater", should be put: "how much more"
and as shashank shown below, answer would be 72-32 = 40
and as shashank shown below, answer would be 72-32 = 40
