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If x = (1/2), is y equal to 1?
I] y^2 (2x + 1/2) = 1
II] y (2x - 1) = 2x - y
The OA is B, which was simple but I again made a silly mistake... I need a coffeee.....
Explanation:
statement 1: y^2 (x + 1/2) = 1
therefore, putting the value of x, we get
y^2 = 1
therefore, y = + or - 1
Hence insufficient...
Statement 2: y (2x - 1) = (2x - y)
putting the value of x, we get,
0 = 1 - y
therefore, y = 1.
hence sufficient.
I really do not know how the hell did I commit a mistake here...
I took the equation as y (2x - 1) = 2x - 1
therefore I got the answer as E....
i need a cup of cofffeeeee!!!!
I] y^2 (2x + 1/2) = 1
II] y (2x - 1) = 2x - y
The OA is B, which was simple but I again made a silly mistake... I need a coffeee.....
Explanation:
statement 1: y^2 (x + 1/2) = 1
therefore, putting the value of x, we get
y^2 = 1
therefore, y = + or - 1
Hence insufficient...
Statement 2: y (2x - 1) = (2x - y)
putting the value of x, we get,
0 = 1 - y
therefore, y = 1.
hence sufficient.
I really do not know how the hell did I commit a mistake here...
I took the equation as y (2x - 1) = 2x - 1
therefore I got the answer as E....
i need a cup of cofffeeeee!!!!
IT IS TIME TO BEAT THE GMAT
LEARNING, APPLICATION AND TIMING IS THE FACT OF GMAT AND LIFE AS WELL... KEEP PLAYING!!!
Whenever you feel that my post really helped you to learn something new, please press on the 'THANK' button.
LEARNING, APPLICATION AND TIMING IS THE FACT OF GMAT AND LIFE AS WELL... KEEP PLAYING!!!
Whenever you feel that my post really helped you to learn something new, please press on the 'THANK' button.
