If x = (1/2), is y equal to 1?
I] y^2 (2x + 1/2) = 1
II] y (2x - 1) = 2x - y
The OA is B, which was simple but I again made a silly mistake... I need a coffeee.....
Explanation:
statement 1: y^2 (x + 1/2) = 1
therefore, putting the value of x, we get
y^2 = 1
therefore, y = + or - 1
Hence insufficient...
Statement 2: y (2x - 1) = (2x - y)
putting the value of x, we get,
0 = 1 - y
therefore, y = 1.
hence sufficient.
I really do not know how the hell did I commit a mistake here...
I took the equation as y (2x - 1) = 2x - 1
therefore I got the answer as E....
i need a cup of cofffeeeee!!!!
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Good question... please try all of you...
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I think you made a mistake with statement 1 (above in red)[email protected] wrote:If x = (1/2), is y equal to 1?
I] y^2 (2x + 1/2) = 1
II] y (2x - 1) = 2x - y
According to your solution, the original question should read:
If x = (1/2), is y equal to 1?
I] y^2 (x + 1/2) = 1
II] y (2x - 1) = 2x - y
Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
