The equation formed by decreasing each root of ax^2+bx+c=0 by 1 is 2x^2+bx+2=0, then:
(a) a=-b
(b) b=-c
(c) c=-a
(d) b=a+c
(a) a=-b
(b) b=-c
(c) c=-a
(d) b=a+c
Hi, Interesting q ... Thanks.
I thought the best ways was to assume values for b in the 2nd equation
Let b = -5; The equation becomes 2x^2-5x+2=0
Roots are 1/2 or 2.
Roots of 1st equation are 3/2 or 3
try to form the 1st equation
(x-3/2) (x-3) = 0
Make sure that the coefficients of x match in both the equation. (as they are equal to b).
Only one of the answer choices meet the criteria ... May I reserve the answer at this stage ...
Look forward to know better methods
