Is x > y ?
(1) ax > ay
if a > 0, we can answer the question Is x > y ? YES
if a < 0, we can answer the question Is x > y ? NO
if a = 0, we cannot answer the question Is x > y ? ??
Insufficient
(2) a^2 . x > a^2 . y
if a > 0, we can answer the question Is x > y ? YES
if a < 0, we can answer the question Is x > y ? YES
if a = 0, we cannot answer the question Is x > y ? ??
Insufficient
Option E
x > y
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neelgandham
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Anil Gandham
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pemdas
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agree with st(1) inequality switches signs depending on a +ve or -ve but disagree about st(2)
st(2) should be sufficient as the given condition is ">" and not "=" for 0 on both sides
b
st(2) should be sufficient as the given condition is ">" and not "=" for 0 on both sides
b
neelgandham wrote:Is x > y ?
(1) ax > ay
if a > 0, we can answer the question Is x > y ? YES
if a < 0, we can answer the question Is x > y ? NO
if a = 0, we cannot answer the question Is x > y ? ??
Insufficient
(2) a^2 . x > a^2 . y
if a > 0, we can answer the question Is x > y ? YES
if a < 0, we can answer the question Is x > y ? YES
if a = 0, we cannot answer the question Is x > y ? ??
Insufficient
Option E
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neelgandham
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Thanks for correcting me Pemdas !
pemdas wrote:agree with st(1) inequality switches signs depending on a +ve or -ve but disagree about st(2)
st(2) should be sufficient as the given condition is ">" and not "=" for 0 on both sides
bneelgandham wrote:Is x > y ?
(1) ax > ay
if a > 0, we can answer the question Is x > y ? YES
if a < 0, we can answer the question Is x > y ? NO
if a = 0, we cannot answer the question Is x > y ? ??
Insufficient
(2) a^2 . x > a^2 . y
if a > 0, we can answer the question Is x > y ? YES
if a < 0, we can answer the question Is x > y ? YES
if a = 0, we cannot answer the question Is x > y ? ??
Insufficient
Option E
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
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smackmartine
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IMO B
(1) ax > ay
a(x-y)>0 (a and (x-y) have same signs , but we don't know + or -ve so Insuff )
(2) a^2 . x > a^2 . y
a^2(x-y)> 0
we know that a^2 is positive , so x-y > 0 --> x>y (suff)
(1) ax > ay
a(x-y)>0 (a and (x-y) have same signs , but we don't know + or -ve so Insuff )
(2) a^2 . x > a^2 . y
a^2(x-y)> 0
we know that a^2 is positive , so x-y > 0 --> x>y (suff)
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