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A certain rabbit population quadruples every three years. The population today is \(81\). Exactly six years from today,

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A certain rabbit population quadruples every three years. The population today is \(81\). Exactly six years from today,

by AAPL » Sat May 27, 2023 1:58 pm

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A certain rabbit population quadruples every three years. The population today is \(81\). Exactly six years from today, the entire population will be fed to a pack of wolves. If each wolf eats exactly \(12\) rabbits, how many wolves can be fed using this rabbit population?

A. \(54\)
B. \(81\)
C. \(108\)
D. \(216\)
E. \(324\)

OA C
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Re: A certain rabbit population quadruples every three years. The population today is \(81\). Exactly six years from tod

by swerve » Wed Jun 14, 2023 4:32 pm
AAPL wrote: ↑
Sat May 27, 2023 1:58 pm
 Manhattan Prep

A certain rabbit population quadruples every three years. The population today is \(81\). Exactly six years from today, the entire population will be fed to a pack of wolves. If each wolf eats exactly \(12\) rabbits, how many wolves can be fed using this rabbit population?

A. \(54\)
B. \(81\)
C. \(108\)
D. \(216\)
E. \(324\)

OA C
Since the rabbit population quadruples every \(3\) years, and we have two such periods in
\(6\) years, the rabbit population will become \(81\cdot 4\cdot 4\) after \(6\) years.

We know that each wolf eats \(12=4\cdot 3\) rabbits.

Therefore, we would need \(\dfrac{81\cdot 4\cdot 4}{4 \cdot 3}=108\) wolves to eat the rabbit population.

Hence, the correct answer is option C
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