Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 563 reviewsTarget Test Prep

Kate and her twin sister Amy want to be on the same relay-race team. There are \(6\) girls in the group, and only \(4\)

Expert replies
Post new topic Post Reply
Subscribe topic
Previous Topic Next Topic
Moderator
Posts: 2650
Joined: Sun Oct 15, 2017 1:50 pmFollowed by: 6 members
by BTGmoderatorLU » Sat Jun 10, 2023 2:51 pm
Timer
00:00
Your answer
Difficulty–

right wrong

Pick an answer to see how members did

Source: Manhattan Prep

Kate and her twin sister Amy want to be on the same relay-race team. There are \(6\) girls in the group, and only \(4\) of them will be placed at random on the team. What is the probability that Kate and Amy will both be on the same team?

A. \(1/5\)
B. \(2/5\)
C. \(3/5\)
D. \(4/5\)
E. \(9/10\)

The OA is B
Top
Join the discussion
Source: — Problem Solving |
Junior | Next Rank: 30 Posts
Posts: 20
Joined: Mon Jun 05, 2023 7:34 am

Re: Kate and her twin sister Amy want to be on the same relay-race team. There are \(6\) girls in the group, and only \(

by Asimo3089 » Tue Jun 13, 2023 9:32 am
Source: Manhattan Prep

Hey guys! I found a problem about probability and need help. Here it is:
BTGmoderatorLU wrote: ↑
Sat Jun 10, 2023 2:51 pm
 Kate and her sister Amy want same relay-race team. 6 girls in group, only 4 on team. Probability both Kate and Amy on same team?

A. \(1/5\)
B. \(2/5\)
C. \(3/5\)
D. \(4/5\)
E. \(9/10\)

Correct answer is B
To solve, we find chance that both Kate and Amy on team out of 4 spots.

Out of 6 girls, 2 spots for Kate and Amy, 4 spots left for others. Total outcomes is ways to select 2 girls out of 6, \(C(6, 2)\) or \(\binom{6}{2}\).

Favorable outcomes, where Kate and Amy are on same team, is \(C(4, 2)\) or \(\binom{4}{2}\), since we select 2 girls from remaining 4 spots.

Probability is \(\dfrac{C(4, 2)}{C(6, 2)} = \dfrac{\binom{4}{2}}{\binom{6}{2}}\).

Simplifying, \(\dfrac{6}{15} = \dfrac{2}{5}\).

Therefore, correct answer is B.
Top
Join the discussion