Night reader wrote:Among 95 cars - BMW & Honda in auto-dealer's shop, how many cars are not used?
(1) Of the cars which are used ones, 27 are BMW cars
(2) Of the cars which are not used ones, 35% are Honda cars
As already two grid methods are there, I'm explaining it algebraically.
Say,
- Number of used BMW cars = a
Number of used Honda cars = b
Number of non-used BMW cars = c
Number of non-used Honda cars = d
Thus, (a + b + c + d) = 95
We need to find (c + d) = 95 - (a + b)
Therefore we need to know the value of either c and d or a and b for minimum. Knowing the value of one from each group (say, a and c) does not help to answer the question.
Statement 1: a = 27 => Not sufficient
Statement 2: d = 0.35*(c + d) => 7c = 13d
For c and d to be non-negative integer, c must be divisible by 13 and d must be divisible by 7. Possible pairs of values of c and d are (0, 0), (13, 7), (26, 14), (39, 21) and (52, 28).
=> Not sufficient
1 & 2 together: As a = 27 and total number of cars is 95, (a + c + d) cannot exceed 95. Thus possible values of c and are (0, 0), (13, 7), (26, 14) and (39, 21)
=> Not sufficient
The correct answer is E.
