Since An=An-2+11, it represents an AP with d=11/2 = 5.5(A3=A1+11, A5=A3+11 and so on, So A2 = A1+5.5 & A3=A2+5.5),shrey2287 wrote:122. An=An-2+11, n>2. Is 633 in the sequence?
1) A1=39
2) A2=43
OA : A
nth term of an A.P sequence is given by N=a+(n-1)d, here N = 633 (we want to find whether is in the series or not)
Statement1: a=39, N=633, d=5.5
633=39(n-1)5.5
5.5(n-1)=594
(n-1)=108
n=109
So 633 is 109th term of the series if A1=39 Sufficient
Statement2: 43=39, N=633, d=5.5
633=43(n-1)5.5
5.5(n-1)=590
(n-1)=107.272727.......
n=108.2727.....
since n is a number, it can't be in decimal. Insufficient
Hence, A












