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Justin, Max, and Paul each have a collection of marbles.

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by BTGmoderatorLU » Mon Aug 27, 2018 6:16 pm

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A

B

C

D

E

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Difficulty—

Source: Princeton Review

Justin, Max, and Paul each have a collection of marbles. Justin has 50% fewer marbles than Max has. Max has 30% more marbles than Paul has. If Paul's collection contains 80 marbles, how many marbles does Justin's collection contain?

A. 32
B. 48
C. 52
D. 56
E. 64

The OA is C.
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by GMATGuruNY » Mon Aug 27, 2018 6:45 pm
BTGmoderatorLU wrote:Source: Princeton Review

Justin, Max, and Paul each have a collection of marbles. Justin has 50% fewer marbles than Max has. Max has 30% more marbles than Paul has. If Paul's collection contains 80 marbles, how many marbles does Justin's collection contain?

A. 32
B. 48
C. 52
D. 56
E. 64
Since Max has 30% more than Paul's 80 marbles, Max = 80 + (3/10)(80) = 104.
Since Justin has 50% fewer than Max's 104 marbles, Justin = (1/2)(104) = 52.

The correct answer is C.
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by Jeff@TargetTestPrep » Tue Sep 04, 2018 3:23 am
BTGmoderatorLU wrote:Source: Princeton Review

Justin, Max, and Paul each have a collection of marbles. Justin has 50% fewer marbles than Max has. Max has 30% more marbles than Paul has. If Paul's collection contains 80 marbles, how many marbles does Justin's collection contain?

A. 32
B. 48
C. 52
D. 56
E. 64
We can let j = the number of marbles Justin has, m = the number of marbles Max has and p = the number of marbles Paul has. Thus we can create the following equations:

j = 0.5m

m = 1.3p

and

p = 80

So m = 1.3(80) = 104 and j = 0.5(104) = 52. Justin has 52 marbles.

Answer: C

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