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12 teams!

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by fruti_yum » Sat Aug 01, 2009 5:01 am
If each of the 12 teams participating in a certain tournament plays exactly one game with each of the other teams, how many games will be played?

A. 144 B. 132 C. 66 D. 33 E. 23
OA is c

what's a method to tackle this problem?
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by truplayer256 » Sat Aug 01, 2009 5:04 am
Team 1 will play 11 games with Team 2-Team 12.

Team 2 will play 10 games with Team 3- Team 12.

Team 3 will play 9 games with Team 4- Team 12.

11+10+9+8+7+6+5+4+3+2+1=66 games.
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Re: 12 teams!

by quant-master » Sat Aug 01, 2009 8:43 am
fruti_yum wrote:If each of the 12 teams participating in a certain tournament plays exactly one game with each of the other teams, how many games will be played?

A. 144 B. 132 C. 66 D. 33 E. 23
OA is c

what's a method to tackle this problem?
Each team will play with 11 other teams. Hence each team plays 11 games. Hence a total of 11*12 =132 games but since each game involves two teams divide 132/2 = 66

Thanks,
Quant-Master
https://gmat-quants.blocked - My Blog Updated almost daily with new quant fundas. Find collection of quants question in my blog
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by Rajani » Mon Aug 03, 2009 4:26 am
12 teams 2 teams per match -

12C2- 66 (formula nc2)
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Re: 12 teams!

by shahdevine » Mon Aug 03, 2009 4:31 pm
fruti_yum wrote:If each of the 12 teams participating in a certain tournament plays exactly one game with each of the other teams, how many games will be played?

A. 144 B. 132 C. 66 D. 33 E. 23
OA is c

what's a method to tackle this problem?
This is a combinations problem where order does not matter. There are 12 teams, and only 2 teams selected to play one another.

C(12,2)

(12x11)/2!=66

You got this!!
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Re: 12 teams!

by Scott@TargetTestPrep » Sun Feb 02, 2020 11:02 am
fruti_yum wrote: ↑
Sat Aug 01, 2009 5:01 am
 If each of the 12 teams participating in a certain tournament plays exactly one game with each of the other teams, how many games will be played?

A. 144 B. 132 C. 66 D. 33 E. 23
OA is c

what's a method to tackle this problem?
The number of games played is 12C2 = 12! / (2! x 10!) = (12 x 11) / 2 = 66.

Answer: C

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