BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

is |x| = y-z?

Expert replies
by vineetbatra » Mon Sep 21, 2009 3:14 pm
is |x| = y-z?

1. X+y = z
2. X,0

OA is C
Why is A wrong.

x+y = z => x=z-y => x = -Y+Z => -x = y-z. since X is absolute above equation proves true.

what is incorrect in my thinkning.
Join the discussion
Source: — Data Sufficiency |

Re: is |x| = y-z?

by Brent@GMATPrepNow » Mon Sep 21, 2009 5:34 pm
vineetbatra wrote:is |x| = y-z?

1. X+y = z
2. X,0

OA is C
Why is A wrong.

x+y = z => x=z-y => x = -Y+Z => -x = y-z. since X is absolute above equation proves true.

what is incorrect in my thinkning.
To see what's wrong with (1), it's probably easiest to examine two sets of numbers that satisfy the conditions in statement (1) but yield conflicting answers to the question "is |x| = y-z?"
a) x=1, y=2, and z=3 --> here |x| DOES NOT equal y-z?
b) x=-1, y=3, and z=2 --> here |x| DOES equal y-z?
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by vineetbatra » Mon Sep 21, 2009 5:40 pm
Thanks for the reply Brent, but algebrically what is wrong in the way I tried to solve the question. I am trying to find a fault in my approach, as in which rule I violated.
Join the discussion

Re: is |x| = y-z?

by Brent@GMATPrepNow » Mon Sep 21, 2009 5:58 pm
vineetbatra wrote:is |x| = y-z?

1. X+y = z
2. X,0

OA is C
Why is A wrong.

x+y = z => x=z-y => x = -Y+Z => -x = y-z. since X is absolute above equation proves true.

what is incorrect in my thinkning.
Here's the problem: x+y = z => x=z-y => x = -Y+Z => -x = y-z
While all of the above conclusions are correct, we can't then conclude that |x|=y-z.
The conclusion is true if x is a negative number.
However, if x is positive, we have a problem (see my earlier sets of numbers to see this).
If x is positive then y-z is a negative number.
So, when we find the abolute value of x, the result is positive. But, this positive value is supposed to be (by your conclusion) equal to y-z, which happens to be a negative value.
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by grockit_jake » Tue Sep 22, 2009 9:14 am
|x| = y-z?

1. X+y = z
2. X,0


I would rearrange 1. to read x = z - y

Only if x is negative, will taking the absolute value switch its sign. (This would then switch the sign of (z - y), which leaves you at (y - z).

So A is insufficient, since if x > 0, then the answer is no, and if x<0 the answer is yes.

2. Clarifies this.

Answer C
Jake Becker
Academic Director
Grockit Test Prep
https://www.grockit.com
Join the discussion