Is (x-y)/9 an integer?

D is ans here.

Both the statements are basically telling the same thing !

From 1 : they have same two digits but in reverse order.

let's take 12 which is greater than 10.Reverse of it's 21 and diff. is 9 and is divisile by 9 obviously.if you try with any other combination i.e. say 13 am 31 here the diff is 18 and so on ... so the series contains all multiples of 9.sufficient.

Stem 2: just says the same thing in a different ways.i.e. 13 and 31 proves that.So sufficient.

amitansu wrote:D is ans here.

Both the statements are basically telling the same thing !

From 1 : they have same two digits but in reverse order.

let's take 12 which is greater than 10.Reverse of it's 21 and diff. is 9 and is divisile by 9 obviously.if you try with any other combination i.e. say 13 am 31 here the diff is 18 and so on ... so the series contains all multiples of 9.sufficient.

Stem 2: just says the same thing in a different ways.i.e. 13 and 31 proves that.So sufficient.

There is a problem in your reasoning for (B). X can be 42 and Y can be 79

This can be solved with eq

(A) X = 10a+b
Y = 10b+a

X-Y = 9a-9b = 9 (a-b) so sufficient

(B) X = 10 (a+2) + a = 11a+20
Y = 10 (b-2) + b = 11b - 20
X-Y = 11(x-y) + 40

when (x-y)=2 then it is div when x-y = 1 it is not so insufficient

Ans should be A

X-Y = 11(a-b) + 40

a-b=1 51/9 No
a-b=2 62/9 No
a-b=0 40/9 No
a-b=-1 29/9 No
a-b=-2 18/9 Yes

Official answer is 'A'

Thanks,
Vikas