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is x^3 > y?

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by sanju09 » Mon Mar 12, 2012 2:44 am
If x and y are positive, is x^3 > y?
(1) √x > y.
(2) x > y.
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Source: — Data Sufficiency |

by Anurag@Gurome » Mon Mar 12, 2012 6:23 am
sanju09 wrote:If x and y are positive, is x^3 > y?
(1) √x > y.
(2) x > y.
(1) √x > y
If x = 4, y = 1, then 2 > 1 and x^3 = 4^3 = 64 > 1. Here x^3 > y.
If x = 1/4, y = 1/3, then 1/2 > 1/3 and x^3 = 1/64. Here x^3 < y.
No definite answer; NOT sufficient.

(2) x > y
If x = 4, y = 1, then 4 > 1 and x^3 = 4^3 = 64 > 1. Here x^3 > y.
If x = 1/2, y = 1/3, then 1/2 > 1/3 and x^3 = 1/8. Here x^3 < y.
No definite answer; NOT sufficient.

Combining (1) and (2), If x = 4, y = 1, then √x > y and x > y. Here x^3 > y.
If x = 9/16, y = 1/2, then √x = 3/4. Here √x > y and x > y. Here x^3 < y.
No definite answer; NOT sufficient.

The correct answer is E.
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by killer1387 » Mon Mar 12, 2012 6:26 am
IMO E
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by GMATGuruNY » Mon Mar 12, 2012 7:17 pm
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