BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Is |x|< 1?

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 882
Joined: Fri Feb 20, 2009 2:57 pm
Thanked: 15 times
Followed by:1 members
GMAT Score:690

Is |x|< 1?

by crackgmat007 » Sat Jun 27, 2009 10:59 am
Is &#9168;|x|&#9168;< 1?
(1) &#9168;|x + 1|&#9168; = 2&#9168;|x - 1|&#9168;
(2) &#9168;|x - 3|&#9168; &#8800; 0

OA - C Pls explain
Top
Source: — Data Sufficiency |
User avatar
Master | Next Rank: 500 Posts
Posts: 316
Joined: Mon Sep 22, 2008 12:04 am
Thanked: 36 times
Followed by:1 members

by Morgoth » Sat Jun 27, 2009 11:24 am
|x|&#9168;< 1 ?

this simply means is -1 < x < 1

Statement I
&#9168;|x + 1|&#9168; = 2&#9168;|x - 1|&#9168;

case I
x+1 = 2(x-1)
x+1 = 2x -2
x=3

case II
-x-1 = 2(x-1)
-x-1 = 2x-2
x=1/3

x=1/3 or 3

Insufficient.

Statement II

lx - 3l&#9168; &#8800; 0

x &#8800; 3 or -3

Hence, x could be any of other value

Insufficient.


Combining I & II

x= 1/3

Hence, C.

Hope this helps.
Top
Newbie | Next Rank: 10 Posts
Posts: 5
Joined: Sun Jun 28, 2009 12:58 am

by avigmat11 » Sun Jun 28, 2009 1:51 am
Yes..C..nicely explained by Morgoth.
Thanks
Top
Legendary Member
Posts: 1169
Joined: Sun Jul 06, 2008 2:34 am
Thanked: 25 times
Followed by:1 members

by aj5105 » Mon Jun 29, 2009 2:50 am
Can you please explain how you got two values for statement (2)?

Cause, I am getting just one value. x &#8800; 3.

Morgoth wrote:|x|&#9168;< 1 ?

this simply means is -1 < x < 1

Statement I
&#9168;|x + 1|&#9168; = 2&#9168;|x - 1|&#9168;

case I
x+1 = 2(x-1)
x+1 = 2x -2
x=3

case II
-x-1 = 2(x-1)
-x-1 = 2x-2
x=1/3

x=1/3 or 3

Insufficient.

Statement II

lx - 3l&#9168; &#8800; 0

x &#8800; 3 or -3

Hence, x could be any of other value

Insufficient.


Combining I & II

x= 1/3

Hence, C.

Hope this helps.
Top
User avatar
Master | Next Rank: 500 Posts
Posts: 316
Joined: Mon Sep 22, 2008 12:04 am
Thanked: 36 times
Followed by:1 members

by Morgoth » Mon Jun 29, 2009 5:29 am
aj5105 wrote:Can you please explain how you got two values for statement (2)?

Cause, I am getting just one value. x &#8800; 3.
Thanks for pointing out, statement II should only have value x &#8800; 3,
Top
Post new topic Post Reply
• Page 1 of 1