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gmatdriller
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ans is ddd
from 1: |x + 3| = 4x - 3
if x > 0, than x+3 = 4x -3 by solving this we get 6= 3x. thus x =2
if x< 0, than x +3 = -4x + 3, by solving this we get x =0 . but if we put x=0 in the question than we see that |x + 3| is not equal to 4x - 3. thus x is not equal to 0
(YOU CAN SEE THAT IF WE PUT X=2 IN THE INEQUALITY WE GET |x + 3| = 4x - 3
HENCE X = 2 THUS X >1
IN THE QUESTIONS RELATED TO MODE ALWAYS CROSS VERIFY THE INEQUALITY BY PUTTING VALUE IN THE QUESTION.
FROM 2: |x + 1| = 2x - 1
IF X>0 THAN, X+1 = 2X-1 . bY SOLVING THIS WE GET X= 2
IF X<0 THAN X+1 =2X-1. BY SOLVING THIS WE GET X = 0
PUT BOTH VALUES IN THE ORIGINAL INEQUALITIES. YOU WILL FIND THAT ONLY X=2 HOLD TRUE. THUS X= 2
HENCE ANSWER SHOULD BE D

















