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paresh_patil
- Senior | Next Rank: 100 Posts
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- Joined: Thu Jan 03, 2013 10:30 pm
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Statement 1: x and y are of same sign.paresh_patil wrote:xyz>0, is x>0?
1) xy>0
2) xz>0
Also xy and xyz are of same sign.
Hence, z > 0
But we cannot conclude anything about x.
Not sufficient
Statement 2: x and z are of same sign.
Also xz and xyz are of same sign.
Hence, y > 0
But we cannot conclude anything about x.
Not sufficient
1 & 2 Together: Now we know, both y and z are positive and x is of same sign as of y and z.
Hence, x > 0
Sufficient
The correct answer is C.