Is the point Q on the circle with center C ?

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Is the point Q on the circle with center C ?

(1) R is a point on the circle and the distance from Q to R is equal to the distance from Q to C.
(2) S is a point on the circle and the distance from Q to S is equal to the distance from S to C.

E

Source: Official Guide 2020

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by [email protected] » Thu May 16, 2019 12:56 pm

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Hi All,

We're asked if the point Q is on the circle with center C. This is a YES/NO question and can be approached with some logic (and a few examples/drawings might help).

(1) R is a point on the circle and the distance from Q to R is equal to the distance from Q to C.

Since C is the CENTER of the circle, and R is on the circumference, we know that CR is a RADIUS of the circle. With the information in Fact 1, point Q can be ANY point that is equidistance from R and C.
IF....
-we have an equilateral triangle, with R and Q on the circumference, then the answer to the question is YES.
-we have point Q in the exact middle of the radius CR, then the answer to the question is NO.
Fact 1 is INSUFFICIENT

(2) S is a point on the circle and the distance from Q to S is equal to the distance from S to C.

Since C is the CENTER of the circle, and S is on the circumference, we know that CS is a RADIUS of the circle. With the information in Fact 2, we know that the length of QS is the SAME length as the RADIUS.
IF....
-we have an equilateral triangle, with S and Q on the circumference, then the answer to the question is YES.
-we have point Q in any other position that is exactly one radius in length from point S, then the answer to the question is NO.
Fact 2 is INSUFFICIENT

Combined, we know...
R is a point on the circle and the distance from Q to R is equal to the distance from Q to C.
S is a point on the circle and the distance from Q to S is equal to the distance from S to C.

With both Facts, we can create two different examples:
-we have two equilateral triangles, with Q on the circumference and R and S on opposite sides of Q, then the answer to the question is YES.
-we have an isosceles triangle, with Q OUTSIDE of the circle and CR as the non-equal side, then the answer to the question is NO.
Combined, INSUFFICIENT

Final Answer: E

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AbeNeedsAnswers wrote:
Tue Apr 30, 2019 5:45 pm
Is the point Q on the circle with center C ?

(1) R is a point on the circle and the distance from Q to R is equal to the distance from Q to C.
(2) S is a point on the circle and the distance from Q to S is equal to the distance from S to C.

E

Source: Official Guide 2020
Solution:

Question Stem Analysis:


We need to determine whether point Q is on the circle C, i.e., whether point Q is on the circumference of circle C.

Statement One Alone:

From statement one, we see that Q is on the perpendicular bisector of radius RC. Since the perpendicular bisector of a radius of a circle intersects the circle at two points. Q might or might not be on circle C (that is, if Q is one of the two intersection points, then it’s on the circle; otherwise, it is not). Statement one alone is not sufficient.

Statement Two Alone:

From statement two, we see that Q is on a circle with the same radius as circle C but centered at S. Since such a circle intersects circle C at two points, Q might or might not be on circle C (that is, if Q is one of the two intersection points, then it’s on the circle; otherwise, it is not). Statement two alone is not sufficient.

Statements One and Two Together:

The point Q may or may not be on the circle even when we consider both statements together.

To come up with a scenario where point Q is on the circle, choose points R and S such that the angle RCS is 120 degrees. Choose point Q to be the point where the bisector of the angle RCS meets the circle. Notice that RQC and QCS are both equilateral triangles, and RC and SC are both radii of the circle. Thus, RQ = QC = QS = SC.

For the scenario where point Q is not on the circle, recall that point Q must be on the perpendicular bisector of radius RC. Let S be the one of the points this perpendicular bisector meets the circle. Draw a circle of radius SC = RC with center at S. This circle will intersect the perpendicular bisector in two points and neither of these points will be on the original circle. Notice that: 1) QR is equal to QC because Q is on the perpendicular bisector of RC, and 2) QS is equal to SC because Q is on the circle with center S and radius SC.

As we can see, even when we assume both statements, the point Q may or may not be on the circle with center C.

Answer: E

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