is the largest value of integer n

edit:

I didn't count the 5 in 25 twice. Taking that into account, the answer becomes A



---

Original:


I think it should be C.

6 zeros will be obtained by multiplying 2 & 5, 6 times. This means that 2 and 5 need to occur 6 times maximum in the series.

We get 6 2s with 2, 4, 6, 8.

6 5s --> 5, 10, 15, 20, 25, 30. Therefore, n *has* to be at least 30.

Since we need the biggest n, it should be 34. (35 would lead to there being 7 zeroes)

p=n! and the number of 5 in P is 6
so (n/5)+(n/25)=6..1

only 29 satisfies 1

hence ans option A