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OG 11 Edition 65 problem

Expert replies
by prashanthichennupati » Sat Jun 08, 2013 6:41 pm
If m is an integer, is m odd?

1. m/2 is NOT an even integer
2. m-3 is an even integer

When I solved the problem both statements were valid. I chose D as the answer but the official guide has B as the answer.

Can anyone explain why statement 1 is NOT sufficient?

Thanks in Advance.
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Source: — Data Sufficiency |

by GMATGuruNY » Sat Jun 08, 2013 8:48 pm
prashanthichennupati wrote:If m is an integer, is m odd?

1. m/2 is NOT an even integer
2. m-3 is an even integer

When I solved the problem both statements were valid. I chose D as the answer but the official guide has B as the answer.

Can anyone explain why statement 1 is NOT sufficient?

Thanks in Advance.
Statement 1: m/2 is NOT an even integer
If m=2, then m/2 = 2/2 = 1, which is not an even integer.
In this case, m is even.
If m=3, then m/2 = 3/2 = 1.5, which is not an even integer.
In this case, m is odd.
INSUFFICIENT.

Statement 2: m-3 is an even integer
m-3 = even
m = even + 3 = even + odd = odd.
SUFFICIENT.

The correct answer is B.
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by prashanthichennupati » Sun Jun 09, 2013 7:10 am
Thanks Mitch for the explanation.

Can you explain the statement statement "m/2 is NOT an even integer". Please find my explanation below.

I took the values of
m=2,6,10,14,18 then m/2 is NOT an even integer - all the values of m are integers and are even

I didn't select m=3,5,7 as m/2 is NOT an integer(Value is a decimal).
I didn't select m=4,8,12,16 as m/2 is an EVEN integer

When the statement is stating m/2 is NOT an even integer does that mean the value of m/2 can be an odd integer and also a decimal?Please clarify.
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by ritzzzr » Mon Jun 10, 2013 1:02 am
prashanthichennupati wrote:Thanks Mitch for the explanation.

Can you explain the statement statement "m/2 is NOT an even integer". Please find my explanation below.

I took the values of
m=2,6,10,14,18 then m/2 is NOT an even integer - all the values of m are integers and are even

I didn't select m=3,5,7 as m/2 is NOT an integer(Value is a decimal).
I didn't select m=4,8,12,16 as m/2 is an EVEN integer

When the statement is stating m/2 is NOT an even integer does that mean the value of m/2 can be an odd integer and also a decimal?Please clarify.
It's written in the question "m/2 is not an even integer" which means it can be any value other then even integers & we can select values of m = "3 ,5,7" as they are integers for checking
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by GMATGuruNY » Mon Jun 10, 2013 3:52 am
prashanthichennupati wrote: When the statement is stating m/2 is NOT an even integer does that mean the value of m/2 can be an odd integer and also a decimal?Please clarify.
Correct.
As long as m is an integer, m/2 can be ANY VALUE OTHER THAN AN EVEN INTEGER.
Thus, m/2 can be odd (as when m=6) or a noninteger (as when m=3).
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