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Moe invested

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by sanju09 » Fri Mar 23, 2012 2:49 am
Moe invested a total of $5000 at 5 percent simple annual interest for n years. Is n > 4?
(1) At the end of n years; Moe's investment with interest was more than $5500.
(2) At the end of n years; Moe's investment with interest was less than $6500.
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by neerajkumar1_1 » Fri Mar 23, 2012 4:14 am
statement 1; n could be 4 and more.. so insufficient...

statement 2: n is definitely greater than 5... so sufficient...

IMO: B
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by killer1387 » Fri Mar 23, 2012 4:20 am
sanju09 wrote:Moe invested a total of $5000 at 5 percent simple annual interest for n years. Is n > 4?
(1) At the end of n years; Moe's investment with interest was more than $5500.
(2) At the end of n years; Moe's investment with interest was less than $6500.
imo E
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by klmehta03 » Mon Mar 26, 2012 11:38 am
My answer is E can we have OA pls?
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by klmehta03 » Mon Mar 26, 2012 11:39 am
My answer is E can we have OA pls?
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by diebeatsthegmat » Mon Mar 26, 2012 11:36 pm
sanju09 wrote:Moe invested a total of $5000 at 5 percent simple annual interest for n years. Is n > 4?
(1) At the end of n years; Moe's investment with interest was more than $5500.
(2) At the end of n years; Moe's investment with interest was less than $6500.
i think the answer should be E...
the formular is F=year*interest*the sum of money, so
statement1 n could be any number from 3
statement 2: interest <6500 so the min interest moe could get is 1500 so n should be 6 and 6, n,4..
both is also insufficient
E
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by spartacus1412 » Tue Mar 27, 2012 12:03 am
from statement 1 : n >2
from statement 2 : n <6

none of them prove n >4 alone.

when combined 2<n<6.
hence, E.
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