oldheaven wrote:x,y>0 .If xy=6 then what is the minimum of 3x+5y ?
1)6sqrt(10)
2)sqrt(30)
3)2sqrt(10)
4)3aqrt(6)
Minimum
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- tomada
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What's the OA?
I'm really old, but I'll never be too old to become more educated.
- neelgandham
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Please don't shower bats at me for solving this question, this way !
If x,y>0, xy=6 then what is the minimum of 3x+5y ?
1)6sqrt(10)
2)sqrt(30)
3)2sqrt(10)
4)3aqrt(6)
xy = 6, Implies y =6/x
The expression 3x + 5y = 3x + (30/x) = (3x^2 + 30)/x
Maximum/Minimum value of a function f(x) can be found by initially finding the value of x that satisfies the equation f '(x) = 0 (where f '(x) is the derivative of f(x)) and then substitution the value of x in the function f(x).
f(x) = (3x^2 + 30)/x
f'(x) = (3x^2 - 30)/x^2 = 0 ; x =√10 and the derivative of f'(x)>0(which tells us that f(x) at x =√10 is minimum)
The expression 3x + 5y = 3x + (30/x) = 3√10 +(30/√10) = 6√10 A
Derivative formulae -> https://math.about.com/library/weekly/aa021003a.htm- I used rule #9
If x,y>0, xy=6 then what is the minimum of 3x+5y ?
1)6sqrt(10)
2)sqrt(30)
3)2sqrt(10)
4)3aqrt(6)
xy = 6, Implies y =6/x
The expression 3x + 5y = 3x + (30/x) = (3x^2 + 30)/x
Maximum/Minimum value of a function f(x) can be found by initially finding the value of x that satisfies the equation f '(x) = 0 (where f '(x) is the derivative of f(x)) and then substitution the value of x in the function f(x).
f(x) = (3x^2 + 30)/x
f'(x) = (3x^2 - 30)/x^2 = 0 ; x =√10 and the derivative of f'(x)>0(which tells us that f(x) at x =√10 is minimum)
The expression 3x + 5y = 3x + (30/x) = 3√10 +(30/√10) = 6√10 A
Derivative formulae -> https://math.about.com/library/weekly/aa021003a.htm- I used rule #9
Anil Gandham
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- tomada
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I love it! Well done! Do we need to know calculus for the GMAT?
neelgandham wrote:Please don't shower bats at me for solving this question, this way !
If x,y>0, xy=6 then what is the minimum of 3x+5y ?
1)6sqrt(10)
2)sqrt(30)
3)2sqrt(10)
4)3aqrt(6)
xy = 6, Implies y =6/x
The expression 3x + 5y = 3x + (30/x) = (3x^2 + 30)/x
Maximum/Minimum value of a function f(x) can be found by initially finding the value of x that satisfies the equation f '(x) = 0 (where f '(x) is the derivative of f(x)) and then substitution the value of x in the function f(x).
f(x) = (3x^2 + 30)/x
f'(x) = (3x^2 - 30)/x^2 = 0 ; x =√10 and the derivative of f'(x)>0(which tells us that f(x) at x =√10 is minimum)
The expression 3x + 5y = 3x + (30/x) = 3√10 +(30/√10) = 6√10 A
Derivative formulae -> https://math.about.com/library/weekly/aa021003a.htm- I used rule #9
I'm really old, but I'll never be too old to become more educated.
- neelgandham
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Thanks Tomada ! and I am sure that you need not have knowledge of calculus for the GMAT(Knowing some formulae doesn't hurt, and sometimes helps as in this case). I am sure we can solve this in a better(read using algebra) way.So, let us wait for the experts to reply!
Anil Gandham
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There is an algebraic solution, but this still seems to be a very unGMATlike question in that it only has four answer choices and is extremely difficult. I think that people who are only interested in the GMAT would be wise to skip this question.neelgandham wrote:Thanks Tomada ! and I am sure that you need not have knowledge of calculus for the GMAT(Knowing some formulae doesn't hurt, and sometimes helps as in this case). I am sure we can solve this in a better(read using algebra) way.So, let us wait for the experts to reply!
I think the more important matter, though, is the origin and meaning of the phrase "please don't shower bats at me"
- GmatMathPro
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Okay I just read some of your other posts explaining the source of these questions. You say it's some kind of GMAT-like test in Iran? If you post a non-standard GMAT question, I think it's important to note the source so that other people don't get worried if it seems way too hard for them.oldheaven wrote:x,y>0 .If xy=6 then what is the minimum of 3x+5y ?
1)6sqrt(10)
2)sqrt(30)
3)2sqrt(10)
4)3aqrt(6)
That said, one way to solve this algebraically is as follows:
xy=6 and we're trying to minimize the value of 3x+5y. Let 3x+5y=b. So if we consider all the possible values of x and y that satisfy xy=6, we can plug these into 3x+5y=b, which would give us a value b. Our job is to find the lowest possible value of b. xy=6---->y=6/x. Plug this in to 3x+5y=b to get 3x+5(6/x)=b:
3x+30/x=b
Multiply both sides by x:
3x^2+30=bx
3x^2-bx+30=0
For this to have a solution, the discriminant must be non-negative, so
b^2-4ac>=0
b^2-4(3)(30)>=0
b^2-360>=0
b^2>=360
We're only considering x,y>0, so
b>=√360
b>=6√10
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pemdas
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and to be more precise with calculus ...neelgandham wrote:Please don't shower bats at me for solving this question, this way !
If x,y>0, xy=6 then what is the minimum of 3x+5y ?
1)6sqrt(10)
2)sqrt(30)
3)2sqrt(10)
4)3aqrt(6)
xy = 6, Implies y =6/x
The expression 3x + 5y = 3x + (30/x) = (3x^2 + 30)/x
Maximum/Minimum value of a function f(x) can be found by initially finding the value of x that satisfies the equation f '(x) = 0 (where f '(x) is the derivative of f(x)) and then substitution the value of x in the function f(x).
f(x) = (3x^2 + 30)/x
f'(x) = (3x^2 - 30)/x^2 = 0 ; x =√10 and the derivative of f'(x)>0(which tells us that f(x) at x =√10 is minimum)
The expression 3x + 5y = 3x + (30/x) = 3√10 +(30/√10) = 6√10 A
Derivative formulae -> https://math.about.com/library/weekly/aa021003a.htm- I used rule #9
f(x) = (3x^2 + 30)/x = 3x + 30*x^-1 and df/dx = f`(x) = 3 - 30/x^2
Equating this to 0 (zero) implies either maximum or minimum => 3 - 30/x^2 = 0; 3 = 30/x^2, x^2= 10 and x=sqrt(10). To understand this is minimum of f(x) we take the second derivative, d^2f/dx^2=f``(x)=(3-30/x^2)'=(-30*x^-2)'=60/x^3. Since x>0 60/x^3>0 and we have minimum of f(x) in the point x=sqrt(10). No we supply this into original function f(x) = (3x^2 + 30)/x and find f(x) = (30+30)/sqrt(10)=60/sqrt(10)=6sqrt(10)
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Since this thread is still alive and kicking, I want to make it clear that the question is out of scope.
Cheers,
Brent
Cheers,
Brent
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Thanks Brent your post gave some relief to me.Brent@GMATPrepNow wrote:Since this thread is still alive and kicking, I want to make it clear that the question is out of scope.
Cheers,
Brent
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To chime in as well...
- you definitely never need calculus on the GMAT. I doubt there are many places where it would even be helpful.
- this question is out of scope not only because it is so difficult, but because of the wording. "What is the minimum [of some expression]" is a bit vague. The GMAT would instead ask for a minimum value. Also, x,y>0 is not a standard formulation - you won't find commas within an equation/inequality.
- did we ever get an answer on what "don't shower me with bats" means??
- you definitely never need calculus on the GMAT. I doubt there are many places where it would even be helpful.
- this question is out of scope not only because it is so difficult, but because of the wording. "What is the minimum [of some expression]" is a bit vague. The GMAT would instead ask for a minimum value. Also, x,y>0 is not a standard formulation - you won't find commas within an equation/inequality.
- did we ever get an answer on what "don't shower me with bats" means??
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education
EdM in Mind, Brain, and Education
Harvard Graduate School of Education













