Yep, definitely want to factor the initial statement before doing anything else. Just wanted to add a little clarification.
Why do we know that even*odd*even is div. by 4, when we don't know if odd*even*odd is?
The only thing we do know is that an even number is divisible by 2. We know nothing universal about div. of odd numbers. If we have two even numbers in the group, then we have two 2's, or (2x2) = 4, so the product of the three numbers is definitely div. by 4. If we have only one even number in the group, then we know the product of the three numbers is definitely div. by 2, but it may or may not be div. by 4.
Also, how do we know statement 1 tells us x is div. by 4? If you add or subtract any numbers which share the same factor(s), then the sum or difference will also have that same factor. So, for statement 1: 4y+4 (and y is integer), the two numbers have 4 as a factor. Therefore, the sum of the two numbers will also have 4 as a factor. That sum, of course, equals x, so x has 4 as a factor.
Statement 2 only tells us that 2 is a factor of x, so we have to take it one more step. If 2 is a factor of x, then x is even. If x is even, then our product is even*odd*even, which we know works b/c of our initial analysis, above.
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