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chaitanya.mehrotra: Master | Next Rank: 500 Posts; Posts: 184; Joined: Thu Nov 25, 2010 9:57 pm; Thanked: 1 times; Followed by:5 members; GMAT Score:700

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by chaitanya.mehrotra » Sun Jul 10, 2011 9:59 am

In the first hour of the bake sale student sold either candy A which sold for Â£1.3 or Candy B which sold for Â£1.5. What is the ratio of the Candy A sold to Candy B during the first half of the sale.

a)The average price of the candy sold during the first hour was Â£1.42
b)Total price of all the goods sold was Â£14.2

OA D

[spoiler]Doubt: Are one suppose to check even the equation one gets ? I didnt check the equation for option B since there were 2 variable and 1 equation ![/spoiler]

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Source: Beat The GMAT — Data Sufficiency | Sun Jul 10, 2011 9:59 am

ikaplan: Master | Next Rank: 500 Posts; Posts: 181; Joined: Fri Sep 04, 2009 12:06 pm; Thanked: 17 times; Followed by:1 members

by ikaplan » Sun Jul 10, 2011 10:25 am

I would go with D.

If you are confused why Statement (2) is sufficient, please watch the session "Problems on which traditional algebra doesn't work" from 'Thursdays with Ron':

https://vimeo.com/16699881

"Commitment is more than just wishing for the right conditions. Commitment is working with what you have."

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shubhamkumar: Senior | Next Rank: 100 Posts; Posts: 72; Joined: Mon Apr 11, 2011 6:45 pm; Thanked: 2 times

by shubhamkumar » Thu Apr 19, 2012 11:07 pm

ikaplan wrote:I would go with D.

If you are confused why Statement (2) is sufficient, please watch the session "Problems on which traditional algebra doesn't work" from 'Thursdays with Ron':

https://vimeo.com/16699881

Statement 2 can be solved by using the equation 1.3A+1.5B=14.2
or 13A+15B=142
To buy max no of items, make B=0,therefore A+B<11
To buy min no of items, make A=0,therefore A+B>9
Hence A+B=10
Solving further A:B=4:6::2:3

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aneesh.kg: Master | Next Rank: 500 Posts; Posts: 385; Joined: Mon Apr 16, 2012 8:40 am; Location: Pune, India; Thanked: 186 times; Followed by:29 members

by aneesh.kg » Fri Apr 20, 2012 11:11 am

Nice, Tricky problem!

Statement 1:
Average = (Total Revenue)/(Total number of candies)
1.42 = 1.3x + 1.5y/(x + y)
1.42x + 1.42y = 1.3x + 1.5y

The ratio of (x/y) can be obtained from this.
Thus, Statement 1 is SUFFICIENT.

Statement 2:
Total Revenue = 1.3x + 1.5y
14.2 = 1.3x + 1.5y
Prima facie, it seems that this equation cannot be solved for (x/y).
But there is a catch: x and y have to hold integral value. It might be possible that (x,y) hold just one possible integral pair of values for the above condition to be satisfied. And, we must check for that.

Let's multiply both sides by 10 to make it look better.
142 = 13x + 15y
For both x and y to be integers, the only possible solution is x=4 and y=6 (plug-in values for x to find this).
Thus, Statement (2) is also SUFFICIENT.

(D) is the answer.

Aneesh Bangia
GMAT Math Coach
[email protected]

GMATPad:
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neelgandham: Community Manager; Posts: 1060; Joined: Fri May 13, 2011 6:46 am; Location: Utrecht, The Netherlands; Thanked: 318 times; Followed by:52 members

by neelgandham » Fri Apr 20, 2012 4:05 pm

In the first hourof the bake sale student sold either candy A which sold for Â£1.3 or Candy B which sold for Â£1.5. What is the ratio of the Candy A sold to Candy B during the first half of the sale.

a)The average price of the candy sold during the first hour was Â£1.42
b)Total price of all the goods sold was Â£14.2.

Shouldn't the question be 'What is the ratio of the Candy A sold to Candy B during the first hour of the sale ?' ?

Shouldn't the second statement be b)Total price of all the goods sold during the first hour was Â£14.2 ?

Anil Gandham
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