BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

interesting LCM problem - need correct answer

Expert replies
by oops » Fri Jun 08, 2007 12:55 pm
Seems (to me) a good Q from one of the online prep sites. Am posting it only bcoz I am not sure of their answer (which I'll post a lil' later). Hope they dont come after me for copyright violation:

Jane, Chen and Boris start together to travel the same way around a circular path of 20 kms. Their speeds are 4, 5 and 1/2, and 8 kms per hour respectively. When will they meet at the starting point?

(A) 40 hours

(B) 12 hours

(C) 11 hours

(D) 44 hours

(E) 36 hours
Join the discussion
Source: — Problem Solving |

oops wrote:Seems (to me) a good Q from one of the online prep sites. Am posting it only bcoz I am not sure of their answer (which I'll post a lil' later). Hope they dont come after me for copyright violation:

Jane, Chen and Boris start together to travel the same way around a circular path of 20 kms. Their speeds are 4, 5 and 1/2, and 8 kms per hour respectively. When will they meet at the starting point?

(A) 40 hours

(B) 12 hours

(C) 11 hours

(D) 44 hours

(E) 36 hours

.. well the q seems to be incomplete ... it doesnt say wther it is the first, second, third time that they meet at the starting point ..

nywayz the method to solve is to take the LCM of the time it take each athlete to run around the track once .. that is the time taken by them will be 5 hrs, 40/11 hrs , 2.5 hrs .. take their LCM and u will get the time that they take to meet for the first time at the starting point ... then according to the q multiply the answer with 2,3, .. depending on whether the second , third, .. time is asked for..
Join the discussion

by f2001290 » Sat Jun 09, 2007 10:16 am
I will go with A. I used the answer choices to solve this problem.

Since the length of the track is 20kms, the distance covered by Jane after "x" no. of hours to be at the starting point should be a multiple of 20.

Only A(40) satisfies this condition. You can verify this using the case of Jane.
Distance covered by Jane after 40 hours = 4*40 = 160kms
Remaining options doesn't satisfy this condition.
Join the discussion

gabriel wrote:
oops wrote:Seems (to me) a good Q from one of the online prep sites. Am posting it only bcoz I am not sure of their answer (which I'll post a lil' later). Hope they dont come after me for copyright violation:

Jane, Chen and Boris start together to travel the same way around a circular path of 20 kms. Their speeds are 4, 5 and 1/2, and 8 kms per hour respectively. When will they meet at the starting point?

(A) 40 hours

(B) 12 hours

(C) 11 hours

(D) 44 hours

(E) 36 hours

.. well the q seems to be incomplete ... it doesnt say wther it is the first, second, third time that they meet at the starting point ..

nywayz the method to solve is to take the LCM of the time it take each athlete to run around the track once .. that is the time taken by them will be 5 hrs, 40/11 hrs , 2.5 hrs .. take their LCM and u will get the time that they take to meet for the first time at the starting point ... then according to the q multiply the answer with 2,3, .. depending on whether the second , third, .. time is asked for..

Yes, this is what I got (5, 40/11 and 2.5) and I thought the LCM was 200/11, but (as u can see) there is no such answer matching it or any integer multiple of 200/11. So am confused - suspect I am going wrong somewhere.

The given answer is A (40)
Join the discussion

by oops » Sat Jun 09, 2007 2:35 pm
f2001290 wrote:I will go with A. I used the answer choices to solve this problem.

Since the length of the track is 20kms, the distance covered by Jane after "x" no. of hours to be at the starting point should be a multiple of 20.

Only A(40) satisfies this condition. You can verify this using the case of Jane.
Distance covered by Jane after 40 hours = 4*40 = 160kms
Remaining options doesn't satisfy this condition.
This seems like a very good and fast way to solve the problem - and your answer agrees with the given answer. I dont use backsolving often and end up wasting a lot of time.

However, I am still very anxious to know where I am going wrong with the LCM method and why the answer is not 200/11 (plz see previous post).
Join the discussion